What point on the wrapping circle would be the solution to W (x) = (0,-1)? (0, 1) 7 12 2 (-1, 0). 0, 2 (1, 0) 17 12 3 (0, -1) 02019 Gynyon, no. oz=D 플+ 27 Oz=D +2πk O * = * + 2nk

Algebra for College Students
10th Edition
ISBN:9781285195780
Author:Jerome E. Kaufmann, Karen L. Schwitters
Publisher:Jerome E. Kaufmann, Karen L. Schwitters
Chapter13: Conic Sections
Section13.1: Circles
Problem 48PS
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What point on the wrapping circle would be the solution to W (x) = (0,–1)?
(0, 1)
(-)
* 17
7
(-1, 0) .
0, 2x (1, 0)
17
12
(-7,-)
19
(0, -1)
02018 Glynyon, no.
O x =
OX=D +2ㅠ
O x = + 2k
O x =
똥 + 2mk
12
Transcribed Image Text:What point on the wrapping circle would be the solution to W (x) = (0,–1)? (0, 1) (-) * 17 7 (-1, 0) . 0, 2x (1, 0) 17 12 (-7,-) 19 (0, -1) 02018 Glynyon, no. O x = OX=D +2ㅠ O x = + 2k O x = 똥 + 2mk 12
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