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- The force R is the resultant of P and 0. Determine Q and the angle .The length of the position vector r is 240 mm. Determine the rectangular components of (a) r; and (b) the unit vector directed from O toward A.Four parallel forces act on the plate as shown. For the force system shown, find the equivalent resultant force and specify its x and y location from the origin, given: FA = 170 lbs, FB = 240 lbs, FC = 210 lbs, FD = 140 lbs, LX = 16 ft, LY = 14 ft, BY = 5 ft, DX = 6 ft The magnitude of resultant force, FR is: (positive number) FR = lbs The distance from the Origin in the positive X-direction is: X = ft The distance from the Origin in the positive Y-direction is: Y = ft
- Find the magnitude of the resultant force, R, of the following forces using Law of Sine/Cosine. F1=81N 26ᴼ S of W and F2=62N 67ᴼ E of N.Given: F1=30N @ 45⁰, F2=20N @120⁰ and F3=10N @90⁰, Find the resultant force and direction.Forces F, P, and T are concurrent. F is acting up to the right at angle α with respect to the x axis, P is directed down to the right at angle β with respect to the x axis and T is directed to the left along the x axis. Determine: The value of F and α if T=450N, P=250N, β=30^0, and the resultant is 300N acting up to the y axis The value of F and α if T=450N, P=250N, β=30^0, and the resultant is zero. The value of α and β if T=450N, P=250N, F=350N and the resultant is zero
- 1. R is the resultant coplanar-concurrent forces composing of P, T, F, and each Q acting on a body. Find the magnitude of the fourth force Q and its angle with respect to horizontal, if P = 840N directed downward to the left at 20 degrees with the vertical, T = 890N is acting to the right along the horizontal, F = 530N is up to the right at 45 degrees with the horizontal and R = 1300N acting downward to the right 30 degrees with the horizontal. show solution, formula and the sketch of the FBD and pls write legibleThe resultant of the two forces, when they act at an angle of 60° is 14 N. If the same forces are acting at right angles, their resultant is 136 N. Determine the magnitude of the two forces.Three forces act at the same point as shown. Determine the magnitude (N) of the resultant. Consider the following: F1 = 192 N F2 = 62 N F3 = 53 N θ1 = 14° θ2 = 37° x = 2 y = 7
- Using a suitable figure show that the resultant of two co-plainer, concurrent forces 'P' & 'Q' having '0' angle between them, can be written in the form of, R = square root of P^2+ Q^2 + 2PQ cos theta. Hence derive an expression for the resultant force if the angle between the forces is 90°.R is the resultant coplanar-concurrent forces composing of P, T, F, and each Q acting on a body. Find the magnitude of the fourth force Q and its angle with respect to horizontal, if P = 840N directed downward to the left at 20 degrees with the vertical, T = 890N is acting to the right along the horizontal, F = 530N is up to the right at 45 degrees with the horizontal and R = 1300N acting downward to the right 30 degrees with the horizontal. Show your answers in graphucal and analytical methodExercise: - Calculate the magnitude and the direction of the resultant of the two forces: A = (11.7 N, 20ᴼ) B = (14.1 N, 45ᴼ), using the following methods: 1. Mathematical Method 2. Graphical Method (Squares paper sheet can be used) 3. Components method (Squares paper sheet can be used)