What will be the moment of resistance of the rectangular cross-section of size 250 mm and 550 mm (effective) kN-m. (M-20 grade of using limit state method in concrete and Fe- 500 grade of steel) Assume 4-16 o is to be provided as tension steel.
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Q: What will be the moment of resistance of the rectangular cross-section of size 250 mm and 550 mm…
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Q: What will be the moment of resistance of the rectangular cross-section of size 250 mm and 550 mm…
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- Maxinnun allowable stress for steel - 140 MPa Maxinnum allowable stress for ahuminum = 90 MPa Maxinnun allowable stress for brouze - 100 MPa Required: Maximun safe value of axial load P Aluminum A 400 mm Bronze A= 200 mm Steel A= 500 mm 2P 4P 2.5 m 2.0 m 1.5m4 A flanged bolt coupling has ten 12-mm di ameter steel bolts on 500 mm diameter b olt circle and six 16 mm diameter aluminu m bolts on 300 mm diameter bolt circle. T he maximum shear stresses of the materi als are 60 MPa in steel and 40 MPa in al uminum. Use G = 80 GPa for steel and 3 0 GPa for aluminum. What is the maximu m required shear strength of each alumin um bolt to determine the maximum torqu e that can be applied to the system? Dra wing not included in this problem.2- The Tensile stress of AISI 1035 Cold-drawn steel is; (a) 550 MPa. (b) 500 MPa. (c) 450 MPa.
- rectanqular seetion with width bz250 and depth h= 500mm is to carcry a A m %3D design bending moment M= 260KN•M, The conerete is of greade e30 and the tensile steel is of HRB400. The tension reinforzce. ment A, is requined.9-5 A -in-thick steel bar, to be used as a beam, is welded to a vertical support by two fillet welds as illustrated. (a) Find the safe bending force F if the permissible shear stress in the welds is 20 kpsi. (b) In part a you found a simple expression for F in terms of the allowable shear stress. Find the allowable load if the electrode is E7010, the bar is hot-rolled 1020, and the support is hot- rolled 1015. F 16 in Problem 9-5 2 in 2 in -6 inAssume the transformed steel section reaches its allowable bending stress first. Calculate the magnitude of the allowable bending moment that can be applied in this case. Answer: M- i Ib-in.
- A brass sleeve S is fitted over a steel bolt B, and the nut is tightened until it is just snug. The bolt has a diameter of dB = 25 mm, and the sleeve has inside and outside diameters of d1 = 26 mm and d2 = 36 mm, respectively. d2 di dB Sleeve (S) Bolt (B) Calculate the temperature rise AT that is required to produce a compressive stress of 23 MPa in the sleeve. (Use material properties as follows: for the sleeve, as = 21 x 10-6/C and Es = 200 GPa; for the bolt, aB = 10 × 10¬6/°C and EB = 400 GPa.) AT = °C (Round to the nearest whole number.)The light rigid bar ABCD shown is pinned at C and connected to two vertical rods. The bar was initially horizontal, and the rods were stress-free before the load P 20 KN is applied. Shool E-200 GPa A-600mm- L-1 m 2.0 m 0.6 m 1.5 m D. VP-20 KN Aluminum E-70 GPa A-900mm L-1.5 m What is the axial deformation of steel rod in mm?2- A steel pod is stretek between two rigid walls ard carries a tensile Coad 4GO0ON at c f the allowatle Stress is not to excred 130 MPa at -4C, what is the minimum the nd? diameter f ard E= J00 GPa. Figure: ST L
- A brass sleeve S is fitted over a steel bolt B, and the nut is tightened until it is just snug. The bolt has a diameter of dg = 25 mm. and the sleeve has inside and outside diameters of di = 26 mm and dz = 36 mm, respectively. d2 di Sleeve (S), dB Bolt (B) Calculate the temperature rise AT that is required to produce a compressive stress of 24 MPa in the sleeve. (Use material properties as follows: for the sleeve, as = 21 x 10-6/°C and Es = 200 GPa; for the bolt, aB = 10 x 10-6/*C and Eg = 400 GPa.) AT = *C (Round to the nearest whole number.)2m 2m 12₂ 2m y 2N/m ✓ 2N/m 2m $ بلاCurrent Attempt in Progress X Incorrect Compound axial member ABC has a uniform diameter of d- 1.25 in. • Segment (1) is an aluminum [Ez - 10000 ksi]alloy. The length of segment (1) is L4 - 70 in. • Segment (2) is a copper [E2 - 17000 ksi]alloy. The length of segment (2) is L2 - 98 in. When axial force Pis applied, a strain gage attached to copper segment (2) measures a normal strain of 2 - 2100 uin./in. in the longitudinal direction. What is the total elongation of member ABC? L2 Aluminum B Соpper Answer: AL - 35.7 in.