What's wrong? for (int k= 2, k<-12, k+) A the increment should always be ++k B the variable must always be the letter i when using a for loop there should be a semicolon at the end of the statement the commas should be semicolons
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Q: What's wrong? for (int k =2, k<=12, k++) the increment should always be ++k B the commas should be…
A:
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- View the following code, and then answer how many times will this loop run? Enter the exact number of loops in the space provided (as a numeric, not spelt in words). int ammo = 12;void Start(){ while (ammo > 4) { Debug.Log("I have " + ammo + " ammo left."); ammo--; }} Ans:______The following code isn't working correctly and I am unable to figure out why. The for loop is never reached in the first if statement and the program never terminates. May someone please explain to me why that is. #include <stdio.h>#include <time.h>#include <stdlib.h>#include <mpi.h>int main(void){int sum, comm_sz, my_rank, i, next, x;int powTwo = 2;int diff = 1; MPI_Init(NULL, NULL);MPI_Comm_size(MPI_COMM_WORLD, &comm_sz);MPI_Comm_rank(MPI_COMM_WORLD, &my_rank);srandom((unsigned)time(NULL) + my_rank);x = random() % 10;if (my_rank % powTwo == 0){printf("IF----");printf("Process %d generates: %d\n", my_rank, x);for (i = 0; i < comm_sz; i++){MPI_Recv(&x, 1, MPI_INT, i, my_rank , MPI_COMM_WORLD, MPI_STATUS_IGNORE);sum += x;printf("Current Sum=: %d\n", sum);}printf("The new divisor is:%d\n", powTwo);powTwo *= 2;diff *= 2; } else if (my_rank % powTwo != 0) {printf("ELSE----");printf("Process %d generates: %d\n", my_rank, x);MPI_Send(&x, 1,…tgn’sider the Given Loop: For(int i=0;i
- Rewrite the following for loop using a while loop. Assumethe variable, x, has been declared as an integer. for (x = 300; x >= 1; x = x - 3) cout << x << endl;Q2. Let denote the nth Fibonacci number. Construct a sequence of ratios of the form , n = 1, 2, . . . , 30. Does the sequence appear to be converging? Compute the golden ratio . Is the sequence converging to this ratio? (Complete each of the tasks using both the for- and while-loop)What will be the value of x after the following code is executed? int x = 10, y = 20; while (y < 100) { x = x + y; } A) 90 B) 110 C) 210 D) This is an infinite loop.
- int toplam = 0;for (int i = 0; i < 10; i++){if (i % 2 == 1) continue;for (int j = 1; j <= 5; j++){if (i * j > 30) continue;toplam += j;}} What will be the total number of iterations when the code runs?Complete the binary search function below using while loop. int search(int a[], int t, int l, int r) {}a and b are int variables containing values, and a < b.Write a for loop that prints all odd numbers from a to b (both inclusive).(Example: if a=25, b=82, then it will print 25 27 29 .... 79 81)Write only the for loop with its block, nothing else. with java
- I'd like to ask a C programing quesitons. I didnt understand this while loop . Can you explain that ? #include<stdio.h>#include<string.h>#include<ctype.h> int main(){int i,k,c,cs;char s[50]="My Name is Ozi";char arr[5];k=0;puts(s);for(i=0;i<strlen(s);i++){if(isspace(s[i])!=0){arr[k]=i;k++; // K = 3 }} c=strlen(arr);//c number of spaces ... c = 3cs=strlen(s); //cs --> number of characters ... cs = 14while(c>=0){for(k=arr[c-1]; k<cs; k++) //i dont understand this while loop can you explain this loop sir ?{ //like k = arr[c-1] ---> why ? printf("%c",s[k]); }cs=arr[c-1];c--; if(c==0){printf(" "); }} }Consider the following code segment. What is the value of i and sum2 after the for loop completes? int sum2 = 0, i = 0; for (int i = 0; i < 5; i++) sum2 = sum2 + i; cout << "Sum is: " << sum2 << " i is: " << i << endl;I need to convert this to a do while loop but I don't know how int firstNum, secNum, oddNum, evenSum, oddSum;//a.cout << "Enter two integers numerically: ";cin >> firstNum >> secNum;if(secNum < firstNum){cout << "Please enter in numerical order." << endl;}//end of ifelse{for(int x = firstNum; x <= secNum; x++){if(x % 2 == 0){evenSum += x;}//end of ifelse{cout << x << ", ";oddSum += x * x;}//end of else oddNum++; }//end of for//b.cout << "are the odd numbers between " << firstNum << " and " << secNum << "." << endl << endl;//c.cout << "The sum of the even numbers is: " << evenSum << endl << endl;//d.int y;y = 1;cout << "Numbers between 1 and 10 with their squares: " << endl;while(y <= 10){cout << y << " " << y*y << endl;y++;}//end of while//e.cout << "Sum of the odd numbers: " << oddSum << endl; }//f.for(char ch = 'A';…