When an air-filled parallel-plate capacitor is connected to a 28 V battery, it contains 80 µC of charge. After disconnecting the capacitor from the battery, the distance between two parallel plates is now reduced to half. (a) What is its new capacitance? Cnew = uF (b) What is the new potential difference between two plates? Vnew = volts (c) Find the energy stored in the new capacitor. Unew =
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