WHEN BOBBING FOR APPLES, IT WAS FOUND THAT A WHOLE CYCLE FOR BOBBING = 0.7 SECONDS IF THE APPLE WAS INITIALLY DISPLACED BY 0.03m-FIND THE FOLLOWING: GIVEN: PERIOD OF OSCILLATION OF APPLES = 0.7 SECONDS FREQUENCY OF OSCILLATION OF APPLES: 1.4.28 Hz ANGULAR FREQUENCY = 8.97 rad/s FIND: OSCILLATION = AMPLITUDE OF POSITION OF APPLE AFTER VELOCITY OF APPLE AFTER 5 ACCELERATION OF APPLE AFTER 5 SECONDS 5 SECONDS SECONDS. m m/s m/s 2
WHEN BOBBING FOR APPLES, IT WAS FOUND THAT A WHOLE CYCLE FOR BOBBING = 0.7 SECONDS IF THE APPLE WAS INITIALLY DISPLACED BY 0.03m-FIND THE FOLLOWING: GIVEN: PERIOD OF OSCILLATION OF APPLES = 0.7 SECONDS FREQUENCY OF OSCILLATION OF APPLES: 1.4.28 Hz ANGULAR FREQUENCY = 8.97 rad/s FIND: OSCILLATION = AMPLITUDE OF POSITION OF APPLE AFTER VELOCITY OF APPLE AFTER 5 ACCELERATION OF APPLE AFTER 5 SECONDS 5 SECONDS SECONDS. m m/s m/s 2
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![IT WAS FOUND
WHEN BOBBING FOR APPLES
THAT A WHOLE CYCLE FOR BOBBING = 0.7 SECONDS
INITIALLY DISPLACED
BY
IF THE APPLE WAS
10.03m-FIND THE FOLLOWING:
GIVEN: PERIOD OF OSCILLATION OF APPLES = 0.1 SECONDS
FREQUENCY OF OSCILLATION OF APPLES: 1.428 Hz
ANGULAR FREQUENCY = 8.97 rad/s
FIND:
AMPLITUDE OF
POSITION OF APPLE AFTER
5 SECONDS
VELOCITY OF APPLE AFTER 5 SECONDS.
ACCELERATION OF APPLE AFTER 5 SECONDS
OSCILLATION =
m
m
m/s
m/s2](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ffe8aa603-110e-436f-a4a7-4809333a6c6d%2Ff3b45e5c-0419-4d62-90fa-aaf51b9b8fa6%2Fc9dio2u_processed.jpeg&w=3840&q=75)
Transcribed Image Text:IT WAS FOUND
WHEN BOBBING FOR APPLES
THAT A WHOLE CYCLE FOR BOBBING = 0.7 SECONDS
INITIALLY DISPLACED
BY
IF THE APPLE WAS
10.03m-FIND THE FOLLOWING:
GIVEN: PERIOD OF OSCILLATION OF APPLES = 0.1 SECONDS
FREQUENCY OF OSCILLATION OF APPLES: 1.428 Hz
ANGULAR FREQUENCY = 8.97 rad/s
FIND:
AMPLITUDE OF
POSITION OF APPLE AFTER
5 SECONDS
VELOCITY OF APPLE AFTER 5 SECONDS.
ACCELERATION OF APPLE AFTER 5 SECONDS
OSCILLATION =
m
m
m/s
m/s2
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