When evaluating the following integral 16dr using trigonometric substitution, Part A The correct substitution for is r=4 sec 8: Answer= (enter T=true and F=false) and dr is 4 sec 0 tan 6 d0 dr: Answer= (enter T=true and F=false) %3D Part B After evaluating the integral 1dr using trigonometric substitution., the correct anti derivative will be Va -16-4sec (x/4) +C Answer= Kenter T=true and F=false)

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