When finding an inverse by hand, the original matrix is written in augmented form. 1 -1 1 1 -1|0 1 6 -2 -30 0 1 The goal is to get the left side to be the identity matrix, which yields the inverse on the right. About halfway through this process of finding Reduced Row Echelon Form, this matrix is achieved where the leading coefficient of each row is either a 0 or a 1. Start with the augmented matrix above and then follow the mathematical instructions below: R2 = R2 – RỊ R3 = R3 – 6R1 R3 = R3 – 4R2 1 b| d f] a e This results in: 0 1 c|g h j 0 0 1| k m Which of the following would be the correct solution after these 3 steps have been applied? 1 -1 2 1 6. 1 -1 -1 -2 -1 1 1 -1 1 1 -1 -1 1 -2 -4 1 1 1 -3 1 3 2 -4 0 0 1-1 -1 1 -3 2 -2 -3 1 -6-3 -3 1 -2 -4 1

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Q: Find the inverse of the matrix if it exists.

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