When the cells are connected in parallel, then * O The current increases The current decreases O The emf increases O The emf decreases
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- Convert the following figure to current source and find I source? * R1 1.2K RL1 27.6V 2.5K 230 mA 23 mA 320 mA O 32 mACells are connected in parallel to increase the current output. In the figure below, if the three (3) cells are connected in parallel, the voltage is Blank 1 V. Tisv Tiov Tisv T1ov T1.5 VK=62 in the circuit, calculate I0 current int he circuit above
- Three resistors of 5, 10, and 15 ohms respectively are connected in series with a 24V source voltage. What is the current in the 5-ohms resistance? a.0.2 A b. 08 Ac. 0.6 A d. 0.5 AIf N1/N2= 4 and the primary voltage is 120 V, what is the secondary voltage?Continuing with the same setup as above, where you connect a 6 Q resistor and a 12 Q resistor in parallel to a 9 V battery Find the total equivalent current, ITot, flowing through the battery in Amperes. RTot ITot R1 R2 BAT1 60 12 Q 9 V
- The solution is incorrect. I tried 400w 100w and 0w and none are correct.Say I have this circuit. How would I use KCL or KVL to find the values of 1.6 A going to the right and 2A going to the left? Confused where those values came from.I am trying to establish the current in the 3 Ohm Resistor and the 24 Ohm Resistor as well as the potential difference between points A and B.
- What is the current through the LED? * R1 330 kOhm LED1 V1 LED red 6 Vd. is a minimum working voltage 79. Which of the following formulas can be used with Ohm's law to determine the amount of voltage necessary to pu ampere of current through ohms of resistance? a. E=IX R E = 0.8 AX 6 E = 4.8 V b. C. d. X₁ = 2 π fL E XL X₁₂=X₁₁+X₁₂+X₁₁ |=Five batteries are connected in parallel to supply a certain load. Each battery consist od 12 cells in series. Each cell has an emf of 2v and the internal resistance of each cell is 0.15ohms. What should be the resistance of the load so that the total power consumed is 384 watts?