When the velocity v of an object is very large, the magnitude of the force due to air resistance is proportional to v² with the force acting in opposition to the motion of the object. A shell of mass 4 kg is shot upward from the ground with an initial velocity of 600 m/sec. If the magnitude of the force due to air resistance is (0.1)v², when will the shell reach its maximum height above the ground? What is the maximum height? Assume the acceleration due to gravity to be 9.81 m/s². dv First write m- -= F(v,t) in terms of the given data. m dv dt

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When the velocity v of an object is very large, the magnitude of the force due to air resistance is proportional to v² with the force acting in opposition to the
motion of the object. A shell of mass 4 kg is shot upward from the ground with an initial velocity of 600 m/sec. If the magnitude of the force due to air resistance
is (0.1)v², when will the shell reach its maximum height above the ground? What is the maximum height? Assume the acceleration due to gravity to be
9.81 m/s².
dv
First write m- -= F(v,t) in terms of the given data.
m
dv
dt
Transcribed Image Text:When the velocity v of an object is very large, the magnitude of the force due to air resistance is proportional to v² with the force acting in opposition to the motion of the object. A shell of mass 4 kg is shot upward from the ground with an initial velocity of 600 m/sec. If the magnitude of the force due to air resistance is (0.1)v², when will the shell reach its maximum height above the ground? What is the maximum height? Assume the acceleration due to gravity to be 9.81 m/s². dv First write m- -= F(v,t) in terms of the given data. m dv dt
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