where W is in kg and t is in years. a. Differentiate this weight function. 2 W'(t) -0.19 (1 = 13.632e The weight of a lake trout as a function of age satisfies the formula W(t) = 23.9(1 – e-0.19t)³, - = Find its second derivative. W"(t) = -2.588e + 10.353e 7.765e Give both the t and W values for any points of inflection (t > 0). t₁ = 0.3375 yr. W(t₂) = = 1 kg. -e-0.19t) -0.191) -0.19t W'(t;) = -0.38t -0.57t The trout is gaining weight most rapidly at this point of inflection. Find this most rapid rate of growth. 0 kg/yr.

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The weight of a lake trout as a function of age satisfies the formula
W(t) = 23.9(1 – e-0.19t)³,
where W is in kg and t is in years. a. Differentiate this weight function.
2
W'(t) = 13.632e-0.19t(1-e e-0.19t) ²
Find its second derivative.
W"(t)
= -2.588e
+ 10.353e
7.765e
Give both the t and W values for any points of inflection (t > 0).
ti
0.3375 yr.
=
W(t₁) =
=
-0.19t
-0.38t
-0.57t
1 kg.
The trout is gaining weight most rapidly at this point of inflection. Find this
most rapid rate of growth.
W'(t;) = kg/yr.
Transcribed Image Text:The weight of a lake trout as a function of age satisfies the formula W(t) = 23.9(1 – e-0.19t)³, where W is in kg and t is in years. a. Differentiate this weight function. 2 W'(t) = 13.632e-0.19t(1-e e-0.19t) ² Find its second derivative. W"(t) = -2.588e + 10.353e 7.765e Give both the t and W values for any points of inflection (t > 0). ti 0.3375 yr. = W(t₁) = = -0.19t -0.38t -0.57t 1 kg. The trout is gaining weight most rapidly at this point of inflection. Find this most rapid rate of growth. W'(t;) = kg/yr.
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