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- Unattached earlobes is dominant to attached earlobes. Two parents, both with unattached earlobes, had a child with attached earlobes. What are the chances that their next child will have attached earlobes? 25% 50% 0% cannot be determined from this infoA man is heterozygous for dimples (Dd) and a carrier for PKU( Pp )disease. He marries a woman who is also heterozygous for dimples and a carrier for PKU disease. Determine the following Genotype of man: __Dd Pp Genotype of woman: ___ Dd Pp Possible gametes of the man: Possible gametes of the woman: Possible phenotypes of their children and the ratio of each:1.Determine the possible kinds of gametes each parent could be produced by: Jane (mother): Tt XcXc IBi -Taster, Color-blind female, Blood type A John (father): tt XcY IAIB- Non-taster, Color-blind male, Blood type AB 2. What percentage of your children would you expect to be boys? Girls?
- . In humans, the condition for normal blood clotting dominates hemophilia. Both alleles are sex-linked to the X chromosome. Two parents produce daughters who are all carriers and sons who are all normal. What are the probable genotypes of the Need the genotype, phenotype gametes and a punnett squareA female has a family history of Duchenne muscular dystrophy, a recessive sex- linked condition that is carried on the X chromosome. She does not have the disease. Her brother, sister, and father all have the disease. while her mother does not. She recently married a male with no family history of the disease. If they decide to have children, what percentage of their sons will have the disease? * 0 0% 0 25% O 50% 0 100%Based on this karyotype, what is the probability that any one of this women's children would would also be carriers for Down's Syndrome? a 100% or 1/1 b 50% or 1/2 c 25% or 1/4 d 10% or 1/10 e None would be carriers
- What are the genotypes of the gametes of the following individuals: a.) BbCCddEe b.) RRggWw c.) ppRR d.) AaTtA male has male pattern baldness, an x-linked recessive trait. Which of the following could be his genotype? Group of answer choices A.) XbYb B.) bb C.) XBY D.) XbYA woman is homozygous dominant for short fingers. She marries a man who is heterozygous for short fingers. What will the punnet square look like
- A couple are both phenotypically normal but their son suffers from hemophilla, a sex linked recessive disorder. What fraction of their children are likely to suffer from hemophilia. what fraction are likely to be carriers.PKU disease is recessive. A man and a woman are both carriers for PKU disease. Determine the following: Genotype of the man: Genotype of the woman: Possible genotypes of children: Possible phenotypes of children: Probability of PKU disease in their children:Suppose a woman has a recessive X-linked disease. Her husband doesnot have the disease. What is the chance that their second child has thedisease?a. 100% c. 25%b. 50% d. 0%