Which is the correct syntax of for loop? while (initialization : condition : update counter): O while (initialization : condition : update counter) [-) O while (condition): while (condition) [ --- )
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- Consider the following for loop. int j, s;s = 0;for (j = 1; j <= 10; j++)s = s + j * (j - 1);In this for loop, identify the loop control variable, the initialization statement, loop condition, the update statement, and the statement that updates the value of s.Write the syntax for a do/while loop that executes as long as a character variable has a value of either “y” or “Y”. (Assume the character variable is already declared, and give it a valid identifier name of your choosing, given that its purpose is to store the user’s response to the question “do you wish to input another set of data?”. You do not need to include any statements in the curly brackets for the loop.) (** How do I do this in c**)What is the major advantage of using a for loop instead of a while loop? a. Unlike with a while loop, the execution of multiple statements can depend on the test condition. b. With a for loop, it is impossible to create an infinite loop. c. It is the only way to achieve an indefinite loop. d. The loop control variable is initialized, tested, and altered all in one place.
- Consider the following for loop. (4) Submit your answer to dropbox. int j,s; s=0; for(j=1; j<=10; j++) s=s+j * (j-1);In this for loop, identify the loop control variable, the initialization statement, loop condition, the update statement, and the statement that updates the value of s.All programming languages have a loop capability. Looping is the program logic’s ability to repeat one or more lines of code either: A set number of times, a “for loop” (i.e. 10, 100, 500, 763 or more times) An “unknown” number of times (i.e. loop terminates if a tested condition becomes “true” or as long as the tested condition remains “false”), a “while” loop, a “do until” loop, a “do while” loop. This Lab exercise demonstrates the use of the “For Loop”, a standard loop in all programming languages. C++ standard For Loop format looks like: For (n = 1; n <= 100; n++) { Loop line 1 code; Loop line 2 code; Loop line 3 code; Loop line N code; } The loop code needs: A “loop counter variable” (n in the above example) to keep track of how many iterations this loop has run A starting value (i.e. 1 in the above example) A stop test (i.e. run as…What is the termination condition (i.e. value of beta) for the following While loop? while (beta > 0 && beta < 10) { cout << beta << endl; cin >> beta; } explain please
- use the c# programming language While and For loops (Solve using all three loops), you may code all three loops in the same project. //do-while loop int counter = 0, stop = 5; //initializer do { Console.WriteLine(counter); //code statement counter++; //updater }while(counter < stop); //checker //while loop int counter = 0, stop = 5; //initializer while(counter < stop) //checker { Console.WriteLine(counter); //code statement counter++; //updater } //for loop // initializer checker updater for(int counter = 0, stop = 5;counter < stop; counter++) { Console.WriteLine(counter); //code statement } Write a program to print the numbers 2 to 10 in increments of two on the same line. The output of your program should be 2 4 6 8 10 Write a Program to compute the sum of eight numbers. You will prompt the user…The purpose of each function should be documented? The purpose of each while-loop should be documented? The program runs def main(): totalBottles = 0 counter = 1 todayBottles = 0 totalPayout = 0 keepGoing = "y" while keepGoing.lower() == "y": totalBottles = getBottles() totalPayout = calcPayout(totalBottles) printInfo(totalBottles, totalPayout) print("Do you want to enter another week’s worth of data?") print("(Enter y or n)") keepGoing = input() def getBottles(): NBR_OF_DAYS = 7 totalBottles = 0 todayBottles = 0 counter = 1 while counter <= NBR_OF_DAYS: print(f"Enter number of bottles returned for day #{counter}:") todayBottles = int(input()) totalBottles += todayBottles counter += 1 return totalBottles def calcPayout(totalBottles): PAYOUT_PER_BOTTLE = .10 totalPayout = totalBottles * PAYOUT_PER_BOTTLE return totalPayout def printInfo(totalBottles, totalPayout):…The problem statement is described in the problem_statement.pdf file. Write the solution into the fuzzy_phrases/solution.py. Please do not change the input and output contract of the def phrasel_search(P, Queries) -> [[string]] function as the testing of the code correctness will be done programmatically. Note - You can only use standard python libraries. ex - json, random, etc So in the screenshots below we have one that has the instructions which has to be followed and executed , the next one that follows should be an example, that says sample example python this is the problem statement supposed to be used to give you an idea , showing how you should take the phrases to loop through the queries as a parameter. The other screenshot is called the solution output, that is the sample of how the code should look like but it has to be modified. and the other screenshot that says this is the first sample py, is the json file you want to loop through . Thank you
- A criticism of the break statement and the continue statement is that each is unstructured.Actually, break statements and continue statements can always be replaced by structured statements, although doing so can be awkward. Describe in general how you would remove any breakstatement from a loop in a program and replace that statement with some structured equivalent.[Hint: The break statement leaves a loop from within the body of the loop. The other way to leaveis by failing the loop-continuation test. Consider using in the loop-continuation test a second testthat indicates “early exit because of a ‘break’ condition.”] Use the technique you developed here toremove the break statement from the program of Fig. 4.11Write the number of for statement/ while loops that will be performed in a C++ program for each of the following: Initialization Condition Update Loops? a) i = 2 i <= 20 i = i + 1 18 b) i = 1 i < 10 i = i + 3 2 c) i = 28 i <= 28 i = i – 1 28 d) i = 1 i > 16 i = i * 4 e) i = -20 i < 50 i = i – 10 f) i = 17 i > 9 i = i – 2 g) i = 14 i != 8 i = i – 2 h) i = 29 while(1) i = i + 1In C++Given positive integer numInsects, write a while loop that prints that number doubled without reaching 200. Follow each number with a space. After the loop, print a newline. Ex: If numInsects = 16, print:16 32 64 128 #include <iostream>using namespace std; int main() {int numInsects; cin >> numInsects; // Must be >= 1 /* Your solution goes here */ return 0;}