QUESTION 6Which of the following will correctly declare, construct and initialize a tow dimensional array of integers?O a. int x[]={{}};O b.int x[]]={1,2};O c. int xI0={{1,2,3},(4,5,6}};O d. int x[]0= new int {123,123};

Here have to determine correct option for array Implementation.

Answered: Which of the following will correctly…

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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I have this problem: You are given an array called source, with length n, and a set of m arrays called target, each alsowith length n. The arrays contain only positive integers. The arrays are unsorted. For any numberx, the smallest number in target[x] is guaranteed to be smaller than target[x+1]. All the numbers intarget are unique. The following figure illustrates an example of valid source and target arrays forthis case, where n=5 and m=6.source = [14, 13, 15, 11, 12] target[0] = [4, 2, 1, 3, 5]target[1] = [6, 8, 7, 10, 9]target[2] = [14, 15, 12, 11, 13]target[3] = [17, 20, 16, 18, 19]target[4] = [22, 21, 24, 23, 25]target[5] = [30, 29, 28, 27, 26]The smallest number in each array in target is styled with bold and italic. You can quickly see thatthe smallest number in target[0] is smaller than the smallest number in target[1], the smallestnumber in target[1] is smaller than the smallest number in target[2], and so on. You can also seethat there is no duplicate number within the…
Question 1. (-) Analyze the below code: #include <stdio.h> int main(void) { int array1[9]; printf("Enter Array1 elements:"); for(int i=0;i<9;i++) scanf("%d",&array1[i]); for(int i=0;i<9;i++) printf("%d ",array1[i]); return 0; } Add code line to print your name (Ghadeer) and take a screenshot for the program output Array elements should be given as: (-) 3 5 7 11 13 17 19 23 31 Explain the code in your own words in details -) Update the code to have float array elements of size 8. (-) Take a screenshot for the program output. Array elements should be given as : (-) 2.3 4…
Suppose we implement the += operator as shown in the following. What goes wrong with b += b ? void bag::operator +=(const bag& addend) // Library facilities used: cassert{ size_type i; // An array index assert(size( ) + addend.size( ) <= CAPACITY); for (i = 0; i < addend.used; ++i) { data[used] = addend.data[i]; ++used; }} Group of answer choices If we activate b += b, then the private member variable size is the same variable as addend.size. The size( ) + addend.size( ) is less than CAPACITY. So the program after the assert statement will be executed. If we activate b += b, then the private member variable size is the same variable as addend.size. The size( ) + addend.size( ) is larger than CAPACITY. So the program after the assert statement will not have chance to be executed. If we activate b += b, then the private member variable used is the same variable as addend.used. Each iteration of the loop adds 1 to used, and hence…
You are given an array called source, with length n, and a set of m arrays called target, each alsowith length n. The arrays contain only positive integers. The arrays are unsorted. For any numberx, the smallest number in target[x] is guaranteed to be smaller than target[x+1]. All the numbers intarget are unique. The following figure illustrates an example of valid source and target arrays forthis case, where n=5 and m=6. source = [14, 13, 15, 11, 12] target[0] = [4, 2, 1, 3, 5]target[1] = [6, 8, 7, 10, 9]target[2] = [14, 15, 12, 11, 13]target[3] = [17, 20, 16, 18, 19]target[4] = [22, 21, 24, 23, 25]target[5] = [30, 29, 28, 27, 26] The smallest number in each array in target is styled with bold and italic. You can quickly see thatthe smallest number in target[0] is smaller than the smallest number in target[1], the smallestnumber in target[1] is smaller than the smallest number in target[2], and so on. You can also seethat there is no duplicate number within the arrays in target. You…
You are given an array called source, with length n, and a set of m arrays called target, each alsowith length n. The arrays contain only positive integers. The arrays are unsorted. For any numberx, the smallest number in target[x] is guaranteed to be smaller than target[x+1]. All the numbers intarget are unique. The following figure illustrates an example of valid source and target arrays forthis case, where n=5 and m=6. source = [14, 13, 15, 11, 12] target[0] = [4, 2, 1, 3, 5]target[1] = [6, 8, 7, 10, 9]target[2] = [14, 15, 12, 11, 13]target[3] = [17, 20, 16, 18, 19]target[4] = [22, 21, 24, 23, 25]target[5] = [30, 29, 28, 27, 26] The smallest number in each array in target is styled with bold and italic. You can quickly see thatthe smallest number in target[0] is smaller than the smallest number in target[1], the smallestnumber in target[1] is smaller than the smallest number in target[2], and so on. You can also seethat there is no duplicate number within the arrays in target. You…
You are given an array called source, with length n, and a set of m arrays called target, each alsowith length n. The arrays contain only positive integers. The arrays are unsorted. For any numberx, the smallest number in target[x] is guaranteed to be smaller than target[x+1]. All the numbers intarget are unique. The following figure illustrates an example of valid source and target arrays forthis case, where n=5 and m=6.source = [14, 13, 15, 11, 12] target[0] = [4, 2, 1, 3, 5]target[1] = [6, 8, 7, 10, 9]target[2] = [14, 15, 12, 11, 13]target[3] = [17, 20, 16, 18, 19]target[4] = [22, 21, 24, 23, 25]target[5] = [30, 29, 28, 27, 26]The smallest number in each array in target is styled with bold and italic. You can quickly see thatthe smallest number in target[0] is smaller than the smallest number in target[1], the smallestnumber in target[1] is smaller than the smallest number in target[2], and so on. You can also seethat there is no duplicate number within the arrays in target. You are…
You are given an array called source, with length n, and a set of m arrays called target, each alsowith length n. The arrays contain only positive integers. The arrays are unsorted. For any numberx, the smallest number in target[x] is guaranteed to be smaller than target[x+1]. All the numbers intarget are unique. The following figure illustrates an example of valid source and target arrays forthis case, where n=5 and m=6.source = [14, 13, 15, 11, 12] target[0] = [4, 2, 1, 3, 5]target[1] = [6, 8, 7, 10, 9]target[2] = [14, 15, 12, 11, 13]target[3] = [17, 20, 16, 18, 19]target[4] = [22, 21, 24, 23, 25]target[5] = [30, 29, 28, 27, 26]The smallest number in each array in target is styled with bold and italic. You can quickly see thatthe smallest number in target[0] is smaller than the smallest number in target[1], the smallestnumber in target[1] is smaller than the smallest number in target[2], and so on. You can also seethat there is no duplicate number within the arrays in target. You are…
You are given an array called source, with length n, and a set of m arrays called target, each alsowith length n. The arrays contain only positive integers. The arrays are unsorted. For any numberx, the smallest number in target[x] is guaranteed to be smaller than target[x+1]. All the numbers intarget are unique. The following figure illustrates an example of valid source and target arrays forthis case, where n=5 and m=6. source = [14, 13, 15, 11, 12] target[0] = [4, 2, 1, 3, 5]target[1] = [6, 8, 7, 10, 9]target[2] = [14, 15, 12, 11, 13]target[3] = [17, 20, 16, 18, 19]target[4] = [22, 21, 24, 23, 25]target[5] = [30, 29, 28, 27, 26] The smallest number in each array in target is styled with bold and italic. You can quickly see thatthe smallest number in target[0] is smaller than the smallest number in target[1], the smallestnumber in target[1] is smaller than the smallest number in target[2], and so on. You can also seethat there is no duplicate number within the arrays in target. You…
1) Consider an integer array a of length n with indexing starting at 0, where n is a positive integer.If the elements of array a are to be written out in reverse order, which of the following C++ code fragment does NOT do the job? Question options: a. int i=n-1; while (i>=1){cout << a[i] << endl; i = i-1;} cout << a[i] << endl; b. int i=n-1; while (i>=1){cout << a[i] << endl; i = i-1;} c. int i=n-1; while (i>=0){cout << a[i] << endl; i = i-1;} d. int i=n; while (i>0){cout << a[i-1] << endl; i = i-1;} 2) Assume we use 8-bit cell to store floating point numbers, 1 bit for sign, 3 bits for excessed exponent, and 4 bits for significand. What is the decimal value for a cell with bit pattern 0 111 1101 Question options: a. 125 b. 224…
A) Starting with a dynamic array of length = 32 and numElements = 30, the length after we execute 90 insert at end operations is [answer]Group of answer choices 120 122 128 none of the above B) In each of the following cases, we start with a dynamic array of length = 128 and numElements = 64. After we execute 30 delete last operations, the number of elements isand the length isAfter we execute 32 delete last operations, the number of elements isand the length isAfter we execute 60 delete last operations, the number of elements isand the length is no hand written
please answer it by c++ write a program that declares an array x of 10 components of type intger initialize tha array so that the first 5 elements are equal to the square of its index and the last 5 components are equal to the reverse of the first 5 elements
Implement the function below. void swap(int pos1, int pos2){} Initial code to be completed: class ArrayList : public List { int* array; int index; int capacity; void dyn_all_add(){ int cap = ceil(capacity * 1.5); array = (int*)realloc(array,cap * sizeof(int)); capacity = cap; } void dyn_all_rem(){ int cap = capacity - (capacity/3); array = (int*)realloc(array,cap * sizeof(int)); capacity = cap; } public: // CONSTRUCTOR ArrayList() { capacity = 4; array = (int*)malloc(capacity); index = 0; } int add(int num) { if (index == capacity){ dyn_all_add(); } *(array + index) = num; index++; return index; } int get(int pos){ if (pos-1 < index){ return *(array + pos-1); } return -1; } int size(){ return index; }…

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Which of the following will correctly declare, construct and initialize a tow dimensional array of integers? O a. int x[]={}; O b. int x[][]={1,2); Oc int x[]]={{1,2,3),(4,5,6}}; O d.int x[O0= new int (123,123);