Which one of the following is FALSE? A A basic block is a sequence of instructions where control enters the sequence at the beginning and exits at the end. B Available expression analysis can be used for common subexpression elimination. C Live variable analysis can be used for dead code elimination D x=4∗5⇒x=20 is an example of common subexpression elimination?
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Which one of the following is FALSE? A A basic block is a sequence of instructions where control enters the sequence at the beginning and exits at the end. B Available expression analysis can be used for common subexpression elimination. C Live variable analysis can be used for dead code elimination D x=4∗5⇒x=20 is an example of common subexpression elimination?
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- Which of the following for-loop control headers results in equivalent numbers of iterations: I and II III and IV I and II have equivalent iterations and III and IV have equivalent iterations. II and IVBelow are two basic blocks of code. Variables used include w, x, y, and z. For each block, determine which variables local to the block are live and which are dead as the statements execute (this is not global liveness analysis). 1. x = 3; y = 4; z = 5; 2. x = y + z; y = x * z;Nxjxjdjskaosoxofjrieididjxsnxnsksmsndnfnfndnejwowo Write a C program called “temp.c” that accepts a temperature in Celsius and prints the corresponding temperature in Fahrenheit. C/5 = (F − 32)/9 Test data and expected output: Enter temp in Celcius: 30.4Temp 30.4 in Celcius = 86.72 Farenheit mssmskdkdkwowodkfkdjdj
- What is the major advantage of using a for loop instead of a while loop? a. Unlike with a while loop, the execution of multiple statements can depend on the test condition. b. With a for loop, it is impossible to create an infinite loop. c. It is the only way to achieve an indefinite loop. d. The loop control variable is initialized, tested, and altered all in one place.Make a flowchart for the below program. #include”mbed.h”; AnalogIn LM35(p15); BusOut control (p21,p22); BusOut SSD(p5,p6,p7,p8,p9,p10,p11,p12); Int main(){ Int MSD=0, LSD=0; control=0x00; While (1) { Float T = LM35*330; MSD = (int) T/10; LSD = (int) T%10; Switch (MSD) { Case 0: SSD=0x3F; break;Case 1: SSD=0x06; break; Case 2: SSD=0x5B; break; Case 3: SSD=0x4F; break; Case 4: SSD=0x66; break; Case 5: SSD=0x6D; break; Case 6: SSD=0x7D; break; Case 7: SSD=0x07; break; Case 8: SSD=0x7F; break; Case 9: SSD=0x6F; break; } Control = 0x01; Wait (0.01); Switch (LSD) { Case 0: SSD=0x3F; break;Case 1: SSD=0x06; break; Case 2: SSD=0x5B; break; Case 3: SSD=0x4F; break; Case 4: SSD=0x66; break; Case 5: SSD=0x6D; break; Case 6: SSD=0x7D; break; Case 7: SSD=0x07; break; Case 8: SSD=0x7F; break; Case 9: SSD=0x6F; break; } Control = 0x02; Wait (0.01); }Write programs for the following problem statements.a) Write a postcondition, event-controlled loop (i.e., a while loop), using a break statement,that prints the numbers 8, 14, 20, 26, 32, and 38 to the terminal (one per line). b) Write a postcondition, event-controlled loop (i.e., a while loop), using a flag variable, that prints the numbers 8, 14, 20, 26, 32, and 38 to the terminal (one per line). c) Write a counter-controlled loop (i.e., a for loop), that prints the numbers 8, 14, 20, 26, 32, and 38 to the terminal (one per line). d) Re-write a), b) and c) so that they print the numbers 38, 32, 26, 14, and 8 to the terminal (one per line). e) Re-write a), b), c), and d) so that they print the numbers to the terminal on the same line separated by spaces.
- Write a c# program that has the followings: • A text will be entered by the user. • After getting the text, the followings will be displayed: First occurence order of each character will be displayed under “Occurence order” title. Character will be displayed under “Character” title. How many times the character is used in the text will be displayed under “Amount of occurence” title. • At page 2, the flowchart of the solution key of this homework is attached. It is not obligatory but you can use the algorithm used in the flowchart.Write a c++ code for a calculator with the following specifications: (a)there are four arithmetic operations (+-*/) to be performed (b)there are four control operations (e, u, d, s) to be managed such that: (i) User enters 'e' to exit or any other key to continue with another expression. (ii) User enters 'u' for up and 'd' for down to scroll through previous expressions the user has entered. (iii) User enters 's' if s/he wishes to redo a previous calculation; in that case, the previously entered operation is executed.Write a C++ program, that will be able to generate 3 random numbers, A-B-C in the range of 15 and 40. The program should ask the user to choose from the following menu, taking into consideration that all operations shall be processed via Function by Reference calls 1- Compute factorial of A, B and C and display the Sum of their factorial2- Check if A > B > C and display their average to the screen 3- Sum of all integers that are divisible by 7 between A and C
- PROBLEM:Write a program that prompts the user to input first name, middle initial, and last name (in upper case) for an ID card. There is a 22-character limit that also includes spaces in between the names on the ID card. The following conditions/limitations are observed: A. If the first name, second name, middle initial, and last name exceed the character limit, use the first name initial and last name. B. If the last name’s character count is greater than or equal to the character limit, omit the second name and middle initial. Use the first name initial and truncate the last name to fit the character limit. C. The spaces in between the first name, second name, middle initial, and last name should not be included in the input. D. If there is no second name or middle initial, input 0. E. Omit any space in the last name, e.g., DE GUZMAN will be DEGUZMAN.What is the output assuming dynamic scoping and static scoping! Give answers for both dynamic and static! #include <iostream> using namespace std; int total = 5; int c = 3; int fun1(int); int fun2(int); int main() { int x = 2; int y = 8; cout << " variables x y and c have values: " << x <<" " << y << " " << c << endl; cout << "main: fun1(x) = " << fun1(x) << endl; cout << " After Call to fun1(x) variables x y and c have values: " << x <<" " << y << " " << c << endl; return 0; } int fun1(int a) { int b = 6; int c = 3; b = total + c + a; cout << "in fun1: b= " << b << endl; cout << "in fun 1 after call to fun2(total) the return value is " << fun2(total) << endl; return (b); } int fun2(int w) { c = c * 2; total = total + w + c; cout << "in fun2: total= " << total << endl; return(c); }Write a function shampoo_instructions() with parameter num_cycles. If num_cycles is less than 1, print "Too few.". If more than 4, print "Too many.". Else, print "N : Lather and rinse." num_cycles times, where N is the cycle number, followed by "Done.". Sample output with input: 2 1 : Lather and rinse. 2 : Lather and rinse. Done. Hint: Define and use a loop variable.