Which quadratic function matches this graph? O f(x) = x² − 14x +45 O f(x)=x²- 11x + 28 O f(x) = x² + 14x +45 6 5 4 3 2 1 -10--8-7 6 5 4 3 2 -19 -1 -2 -5 -6 -7 -8 -9 -101 5 6 7 8 9 1

College Algebra
1st Edition
ISBN:9781938168383
Author:Jay Abramson
Publisher:Jay Abramson
Chapter6: Exponential And Logarithmic Functions
Section6.7: Exponential And Logarithmic Models
Problem 15TI: Cesium-137 has a half-life of about 30 years. If we begin with 200 mg of cesium-137, will it take...
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Which quadratic function matches this graph?
O f(x) = x² - 14x +45
Of(x)=x²-11x + 28
Of(x) = x² + 14x +45
2
O f(x) = x² + 11x + 28
7₁
6
5
4
NW.
3₁
2
1
10 -8-7-65-4-3-2-19
-1
23
-2
-3-
-4
56
-5-
-6
-7-
-8-
809
-9-
-103
x
2 3 4 5 6 7 8 9 10
Transcribed Image Text:Which quadratic function matches this graph? O f(x) = x² - 14x +45 Of(x)=x²-11x + 28 Of(x) = x² + 14x +45 2 O f(x) = x² + 11x + 28 7₁ 6 5 4 NW. 3₁ 2 1 10 -8-7-65-4-3-2-19 -1 23 -2 -3- -4 56 -5- -6 -7- -8- 809 -9- -103 x 2 3 4 5 6 7 8 9 10
9.
inomial 302
O (7x+6)²
(6x - 7)²
O (6x + 7)²
O (7x - 6)²
04x + 49.
10. Iron-59 has a half-life of 44.5 days. How much of a 3.00 mg sample will be left after 222.5 days?
about 6.00 milligrams
about 0.09 milligrams
about 0.03 milligrams
about 0.90 milligrams
Transcribed Image Text:9. inomial 302 O (7x+6)² (6x - 7)² O (6x + 7)² O (7x - 6)² 04x + 49. 10. Iron-59 has a half-life of 44.5 days. How much of a 3.00 mg sample will be left after 222.5 days? about 6.00 milligrams about 0.09 milligrams about 0.03 milligrams about 0.90 milligrams
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