Which statement is TRUE?n+1diverges by Ratio Test.n2 +n+ 1n=D1n+1diverges by Direct Comparison Test compared withn2 +n +1n=1n+1converges by Root Test.n2 + n + 1n=100n+1n+1n² +n+ 1converges because limn→00 n2 + n + 10.n=D100n+1diverges by Limit Comparison Test compared with1.n² +n + 18.8.

Answered: Image /qna-images/answer/c77fd5ac-613d-4a40-89f1-f8abcf41d5ba.jpg

Which statement is TRUE? 00 n+1 diverges by Ratio Test. n2 +n+ 1 n=1 n+1 1 diverges by Direct Comparison Test compared with n2 + n + 1 n=1 n=1 00 n+1 converges by Root Test. n2 +n + 1 n=1 00 n+1 n+1 converges because lim n2 + n + 1 = 0. n→00 n2 + n + 1 n=1 00 n+ 1 diverges by Limit Comparison Test compared with n2 +n + 1 n=1 n=1

Which statement is TRUE? 00 n+1 diverges by Ratio Test. n2 +n+ 1 n=1 n+1 1 diverges by Direct Comparison Test compared with n2 + n + 1 n=1 n=1 00 n+1 converges by Root Test. n2 +n + 1 n=1 00 n+1 n+1 converges because lim n2 + n + 1 = 0. n→00 n2 + n + 1 n=1 00 n+ 1 diverges by Limit Comparison Test compared with n2 +n + 1 n=1 n=1

Algebra & Trigonometry with Analytic Geometry

13th Edition

ISBN:9781133382119

Author:Swokowski

Publisher:Swokowski

Chapter10: Sequences, Series, And Probability

Section10.5: The Binomial Theorem

Problem 14E

See similar textbooks

Similar questions

Find the limit as n -> infinity of ln((9n-7)/(6n+4))?
From the definition of the intergal, we have lim n->infinity 2/n sigmma n k=1 (2+(4k/n)^3)=
Find limn→∞ Z 30sin2(1 − 3e−x/n)e−x/2
Find the limit of the sequencean= 3n−4/2n+3
For ∑ 1/(n - π) and ∑ (n - 1)/(n3 + 1), solve with either big Θ or with Limit Comparison.
can you explain how you got (x-2)=(t-3) and can you explain how you got the new limits because the question doesnt require all this complicated computation the question to be clear is a) converging to alpha less than 0. b) converging to alpha greater than 0. c) conveging to 0. d)diverging
The interval [0,5] is partitioned into nn equal subintervals, and a number xi is arbitrarily chosen in the ith subinterval for each i. Then: lim (n→∞) n ∑ i=1 (2xi−2/n) = ?
n is not a negative integer Given n ≥ 0; justify that limx->∞ fn (x) / ex = 0
Find the limit of (2n!/n!n!)^1/n as n approaches infinity
Show limn→∞(1 +1/2+1/3+···+1/n−lnn) exists
Note: You may need to assume the fact that lim M→+∞ Mne−M = 0 for all n.Sales of the text Calculus and You have been declining continuously at a rate of 2% per year. Assuming that Calculus and You currently sells 4,700 copies per year and that sales will continue this pattern of decline, calculate total future sales of the text. HINT [Use a model of the form Aert.]
Suppose X1,...,Xn are iid Exponential(θ = 2), such that E(Xi) = 2. Further assume that n is large enough that the central limit theorem (CLT) holds. Use the CLT to find the number n, such that P( X-bar < 2.1) > 0.95.