Why buffer solution is used in the determination of Hardness experiment
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- 10 please give the correct ans and the solutionHelp me with Step by step solutionCreep exercises You are involved in a design for high temperature alloys and have performed a rupture test of material A and B. After data analysis, you noticed that the master curve (o vs LMP) of both material A and B coincide as shown in the diagram below. Based on the rupture strength o (MPa) AtB LMP = T(C+ Int) Which material will you select if they both have same constant (CA= CB)? Which material will you select if C < C? Motivate your answer by means of a calculation.
- Stress analysisQuestions: 1. Ceramic specimen has to be immersed in boiling water so as to ensure that water penetration into the pores is effective. State one alternative method that can be used to replace the immersion method in boiling water. 2. In this experiment, density is measured using the Archimedes principle. State one equipment that can be used to measure density of a material. 3. Can density of a powder specimen can be determined?If yes, state one suitable method.difference between 1st principal stress, 2nd principal stress, and 3rd principal stress in mechaninical engineering
- Show solution. Don't round off initial values, round off final ans onlyo (ksi) e (in./in.) 33.2 0.0006 45.5 0.0010 49.4 0.0014 51.5 0.0018 53.4 0.0022 Data taken from a stress-strain test for a ceramic are given in the table. The curve is linear between the origin and the first point. Determine the modulus of elasticity and the modulus of resilience.WHAT IS THIS??????????? I clearly mentioned "Use stress transformation method and not the equations." 10dislike for the above expert Please somebody else solve it using stress transformation method
- Mechanical properties of materials • H.W.: • The following data where obtained during the tensile test of mild steel circular bar 12.75 mm diameter and 203.2 mm gauge length. Determine the following: 1) The apparent stress at each point 2) Strain at each point 3) True stress at each point (Assume D at failure is 8,51 mm and D at max. load is 11.15 mm) 4) Draw stress - strain curved based on: a) Original cross sectional area b) True cross sectional area 5) Proportional limit Mechanical properties of materials 6) Modulus of elasticity 7) Upper and lower yield point 8) Ultimate strength 9) Breaking strength based on the original cross sectional area and on true cross sectional area 10) Percentage of elongation 11) Percentage of reduction in cross sectional area. 12) Ductility, Resilience and toughness Load (N) 4393 16902 29357 33360 33627 35584 41366 48839 52709 55378 56356 43768 Deformation 0.0254 0.127 0.228 0.305 0.356 3.81 6.35 11.68 16.76 26.92 43768 42.42 (mm )what is the formula used in the -δp + δt = -δp + δt = -δp + δt part at the top? what is the difference between the δp and δt? Why do they have different solutions in the following line of working?Table 1 shows the stress-strain data for a new polymeric material rod subjected to an axial load. The last point is observed as the rupture point. Table 1: Stress-strain data for new polymeric matenial Strain, e (dimensionless) Stress, s (Pa) 32 0.1 59 0.2 75 0.3 86 0.4 104 0.5 120 0.6 129 0.7 125 0.8 114 0.9 97 * The yield point is the point on a stress-strain curve that indicates the limit of elastic behaviour and the beginning of plastic behavior. In this case, the yield point occurs at a stress value of 80. Determine the corresponding strain value at the yield point. In any relevant method, use a stopping criterion of 0.05%. e) The ultimate strength is the maxinmum point on the stress-strain curve. This corresponds to the maximum stress that can be sustained by a structure in tension. Compute the ultimate strength point of the polymeric material (strain value that gives maximum stress). In any relevant method, use a stopping criterion of 0.05%. Detemine the absolute error between…
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