why does the local error increase in proportion to the square of the step size but the global error in proportion to the step size in euler's method for solving ODE’s? I am curious and have not been able to find a satisfactory answer
why does the local error increase in proportion to the square of the step size but the global error in proportion to the step size in euler's method for solving ODE’s? I am curious and have not been able to find a satisfactory answer
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter5: Inverse, Exponential, And Logarithmic Functions
Section5.6: Exponential And Logarithmic Equations
Problem 18E
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why does the local error increase in proportion to the square of the step size but the global error in proportion to the step size in euler's method for solving ODE’s? I am curious and have not been able to find a satisfactory answer
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