why is the calculation in the attached image? i know you can switch the lim x->+infinity to limx->0+ by converting (1/x) to (x) in a limit, but what are the intermediate steps in this calculation? Also does this method only apply only to trig questions? Thanks!

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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why is the calculation in the attached image?

i know you can switch the lim x->+infinity to limx->0+ by converting (1/x) to (x) in a limit, but what are the intermediate steps in this calculation? Also does this method only apply only to trig questions? Thanks!

limy = lim
X→∞
X→∞
= lim
x→0+
=
cos(x)
1+x
Cos (0)
1+0
cos (-)
1+1/2+1
= 1
Transcribed Image Text:limy = lim X→∞ X→∞ = lim x→0+ = cos(x) 1+x Cos (0) 1+0 cos (-) 1+1/2+1 = 1
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