The language for the question is C++ (g)Why the code below may generate a error?for (int i ::0; i<= 10; i++)cout << i+;cout << i-+;

Answered: Why the code below may generate a…

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Why the code below may generate a error? for (int i 0; i<= 10; i++) cout << i+; cout << i- +;

Microsoft Visual C#

7th Edition

ISBN:9781337102100

Author:Joyce, Farrell.

Publisher:Joyce, Farrell.

Chapter2: Using Data

Section: Chapter Questions

Problem 17RQ: When you perform arithmetic operations with operands of different types, such as adding an int and a...

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Question

The language for the question is C++

(g)
Why the code below may generate a error?
for (int i ::
0; i<= 10; i++)
cout << i+;
cout << i-+;

Expert Solution

Step 1

The given code:

for( int i=0; i<=10; i++)

cout<<i+-;
cout<<i-+;

In the above cout statement, they try to print the value of i+- and i-+, but in C++ not support +- or -+ unary operator. Therefore, it generate error. Since + and - both are different operator so they need different operand. If it is unary + or - then they must have different operand and they prefix with operand. But if they are binary operator then they mus need two operands but here only one operand is given for both.

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