With the statement, With the statement. int grade-69: if(grade>=70&.&gradec-100) int grade-70; printf("Passed.): if(grade>=70) else if(grade<708&grade>-0 printf("Passed."); printf("Failed.): else printf("Congratulations!"): printf("Invalid Grade!"): What is the output? What is the output? If no break appears in a case, the flow of control will fl to the default case. Congratulations! O Invalid Gradet Passed. Failed. O Tue Passed. O Passed. Congratulations! False O No output. O Passed.Congratulations!

EBK JAVA PROGRAMMING
9th Edition
ISBN:9781337671385
Author:FARRELL
Publisher:FARRELL
Chapter2: Using Data
Section: Chapter Questions
Problem 1CP
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please answer the 3 questions. i will rate you. thanks

With the statement,
With the statement,
int grade-69;
iffgrade>=70&.&grade<=100)
int grade-70;
printf("Passed."):
if(grade>-70)
else if(grade<70&&grade>=0
printf("Passed.");
printf("Failed."):
else
printf("Congratulations!"):
printf("Invalid Grade!"):
What is the output?
What is the output?
Congratulations!
If no break appears in a case, the flow of control willfall to the default case.
Invalid Grade!
Passed.
Failed.
O True
Passed.
Passed.
Congratulations!
O False
No output.
O Passed.Congratulations!
Transcribed Image Text:With the statement, With the statement, int grade-69; iffgrade>=70&.&grade<=100) int grade-70; printf("Passed."): if(grade>-70) else if(grade<70&&grade>=0 printf("Passed."); printf("Failed."): else printf("Congratulations!"): printf("Invalid Grade!"): What is the output? What is the output? Congratulations! If no break appears in a case, the flow of control willfall to the default case. Invalid Grade! Passed. Failed. O True Passed. Passed. Congratulations! O False No output. O Passed.Congratulations!
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