Woite apy thon code to implement amultiplies mulla, 6)that takes two 4 bit numerals and solves their 8 bit produdby using repeated addition algori thm. use fontion adds foraddition and suby for decreaging by 1deverFor enample:n( 101) multiplied by nine { 1001) = ninety aine( l10001)%3Dbecause it eyals 64+32 t2 t1mul (( Trve Tue ,False, True), ( True , false, False , True))( Tive, Tve, false, False, False, Trve , Teve , False)

Woite a py than code to impleme that takes two y bit numerals and solves their 8 bit produd using repeated nddition algori thm. use fintion adds for additiun and suby for decreaying by 1 For enample dever n(n01) multiplied by nine { 1001) = ninety aine (l10001)

Woite a py than code to impleme that takes two y bit numerals and solves their 8 bit produd using repeated nddition algori thm. use fintion adds for additiun and suby for decreaying by 1 For enample dever n(n01) multiplied by nine { 1001) = ninety aine (l10001)

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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/* segvhunt.cFind and eliminate all code that generates Segmentation Fault*/#include <stdio.h>int main() {char **s;char foo[] = "Hello World";*s = foo;printf("s is %s\n",s);s[0] = foo;printf("s[0] is %s\n",s[0]);return(0);}
Q6. Write a function that takes an unsigned integer andreturns the number of '1' bits it has(also known as the Hamming weight).For example, the 32-bit integer '11' has binaryrepresentation 00000000000000000000000000001011,so the function should return 3.T(n)- O(k) : k is the number of 1s present in binary representation.NOTE: this complexity is better than O(log n).e.g. for n = 00010100000000000000000000000000only 2 iterations are required.Number of loops isequal to the number of 1s in the binary representation."""def count_ones_recur(n): Do it.
sub : computer science Pls solve asap.i ll upvote.Thank You Convert this C++ function to an ARM 64 function and please check before bc I've been getting ones that don't assemble or get a segmentation fault.void insertionSort(int arr[], int n) { int i, key, j; for (i = 1; i < n; i++) { key = arr[i]; j = i - 1; // Move elements of arr[0..i-1], // that are greater than key, to one // position ahead of their // current position while (j >= 0 && arr[j] > key) { arr[j + 1] = arr[j]; j = j - 1; } arr[j + 1] = key; } }
#include<iostream>#include<stdlib.h>#include<time.h>#include<bits/stdc++.h>using namespace std; void merge(int arr[], int l, int m, int r){ int n1 = m - l + 1; int n2 = r - m; int L[n1], R[n2]; for (int i = 0; i < n1; i++) L[i] = arr[l + i]; for (int j = 0; j < n2; j++) R[j] = arr[m + 1 + j]; int i = 0; int j = 0; int k = l; while (i < n1 && j < n2) { if (L[i] <= R[j]) { arr[k] = L[i]; i++; } else { arr[k] = R[j]; j++; } k++; } while (i < n1) { arr[k] = L[i]; i++; k++; } while (j < n2) { arr[k] = R[j]; j++; k++; }} void mergeSort(int arr[],int l,int r){ if(l>=r){ return; } int m =l+ (r-l)/2; mergeSort(arr,l,m); mergeSort(arr,m+1,r); merge(arr,l,m,r);} int main(){ srand(time(0)); long int n; cout<<"Enter the number of…
#include<iostream>#include<stdlib.h>#include<time.h>#include<bits/stdc++.h>using namespace std; void merge(int arr[], int l, int m, int r){ int n1 = m - l + 1; int n2 = r - m; int L[n1], R[n2]; for (int i = 0; i < n1; i++) L[i] = arr[l + i]; for (int j = 0; j < n2; j++) R[j] = arr[m + 1 + j]; int i = 0; int j = 0; int k = l; while (i < n1 && j < n2) { if (L[i] <= R[j]) { arr[k] = L[i]; i++; } else { arr[k] = R[j]; j++; } k++; } while (i < n1) { arr[k] = L[i]; i++; k++; } while (j < n2) { arr[k] = R[j]; j++; k++; }} void mergeSort(int arr[],int l,int r){ if(l>=r){ return; } int m =l+ (r-l)/2; mergeSort(arr,l,m); mergeSort(arr,m+1,r); merge(arr,l,m,r);} int main(){ srand(time(0)); long int n; cout<<"Enter the number of…
#include<iostream>#include<stdlib.h>#include<time.h>#include<bits/stdc++.h>using namespace std; void merge(int arr[], int l, int m, int r){ int n1 = m - l + 1; int n2 = r - m; int L[n1], R[n2]; for (int i = 0; i < n1; i++) L[i] = arr[l + i]; for (int j = 0; j < n2; j++) R[j] = arr[m + 1 + j]; int i = 0; int j = 0; int k = l; while (i < n1 && j < n2) { if (L[i] <= R[j]) { arr[k] = L[i]; i++; } else { arr[k] = R[j]; j++; } k++; } while (i < n1) { arr[k] = L[i]; i++; k++; } while (j < n2) { arr[k] = R[j]; j++; k++; }} void mergeSort(int arr[],int l,int r){ if(l>=r){ return; } int m =l+ (r-l)/2; mergeSort(arr,l,m); mergeSort(arr,m+1,r); merge(arr,l,m,r);} int main(){ srand(time(0)); long int n; cout<<"Enter the number of…
In Java This assignment introduces bitwise-manipulation operators (&, |, <<, >>, >>>, ^, and ~),which are not discussed elsewhere in the book. The bitwise-manipulation operators performsimultaneous bit manipulations and enable programs to process large quantities of binaryinformation efficiently. This project is here because the solution uses a conditional operator.The binary & and | operators can implement bitwise “and” and “or” operations oncorresponding bits in a pair of 32-bit int operands. This bit-manipulation capability enablesJava to efficiently process large quantities of raw binary information. We use this capability toencrypt information sent over the Internet and to process graphical images. Suppose you havea 32-bit pattern of 1’s and 0’s in an integer called mask. You can use mask to either set to 1or reset to 0 any subset of the bits in another integer called data:• data |= mask;1 drives to 1 all bits in data that correspond to 1 bits in…
Exercise Fibonacci (Overflow): Write a program called FibonacciInt to list all the Fibonacci numbers, which can be expressed as an int (i.e., 32-bit signed integer in the range of [-2147483648, 2147483647]). The output shall look like: F(0) = 1 F(1) = 1 F(2) = 2 ... F(45) = 1836311903 F(46) is out of the range of int Hints: The maximum 32-bit int is kept in constant Integer.MAX_VALUE. You cannot use F(n-1) + F(n-2) > Integer.MAX_VALUE to check for overflow. Instead, overflow occurs for F(n) if (Integer.MAX_VALUE – F(n-1)) < F(n-2), i.e., no room for the next number. Try: Write a similar program for Tribonacci numbers. Exercise NumberConversion: Write a method call toRadix() which converts a positive integer from one radix into another. The method has the following header: public static String toRadix(String in, int inRadix, int outRadix) // The input and output are treated as String. Write a program called NumberConversion, which prompts the user for an input number, an input…
TODO 3: Invoke the gaussian() function, which accepts x_values, mu, and sig. Save the results in the variable y_values. # TODO 3 y_values = display(y_values) todo_check([ (y_values.shape == (120,),'y_values does not have the correct shape of (120,)'), (np.all(np.isclose(y_values,…
This code is outputting "Abort (core dumped)"please help me fix itWRITTEN IN C LANGUAGE, RUN ON OCELOT #include <stdio.h>#include <unistd.h>#include <stdlib.h> int main(int argc, char *argv[]){int opt;char name[] = "Franco"; while ((opt = getopt(argc, argv, ":if:lrx")) != -1){switch(opt){case 'f': ;FILE *fp;fp = fopen(optarg, "w+");fputs(name, fp);fclose(fp);break; default:abort();}} printf("Name: %s", name);}
c++ 1- Given a set of numbers where all elements occur even number of timesexcept one number, find the odd occurring number” This problem can beefficiently solved by just doing XOR of all numbers.2- Use bitwise operators to compute division and multiplication by a numberthat is power of 2. For example: bitwise_divide/multiply(num,8/16/32/2/4/128) should use only bitwise operators to compute result.3- Write code that checks if a number is odd or even using bitwise operators.4- Write a program that checks if a number is positive/negative/zero.5- Write a function that returns toggle case of a string using the bitwiseoperators in place.
TODO #2: Invoke the gaussian() function, which accepts x_values, mu, and sig. Save the results in the variable y_values. mu = 0 # mean sig = 1 # std # TODO 2 x_values = display(x_values) todo_check([ (x_values.shape == (120,),'x_values does not have the correct shape of (120,)'), (np.all(np.isclose(x_values, np.array([-4.…