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Work Problem 1₁ Consider the DE: (4x + 6y)dy + (-2x + 4y)dx = 0 A) Using only the notations followed in class, Find: M(x, y) = N(x, y) = + af Əy = M(x,y) ◆ = = N(x,y) ; B) Find a function f(x, y) such that: af Əx ; Therefore, we can conclude that the DE is ◆ xy+ f(x, y) = ƏM ду ƏN dx The solution of the IVP is then: f(x, y) = C) Consider the IVP: (4x + 6y)dy + (-2x + 4y)dx = 0 || = " ◆ y(1) = 1

Work Problem 1₁ Consider the DE: (4x + 6y)dy + (-2x + 4y)dx = 0 A) Using only the notations followed in class, Find: M(x, y) = N(x, y) = + af Əy = M(x,y) ◆ = = N(x,y) ; B) Find a function f(x, y) such that: af Əx ; Therefore, we can conclude that the DE is ◆ xy+ f(x, y) = ƏM ду ƏN dx The solution of the IVP is then: f(x, y) = C) Consider the IVP: (4x + 6y)dy + (-2x + 4y)dx = 0 || = " ◆ y(1) = 1

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Work Problem 1, Consider the DE: (4x + 6y)dy + (-2x + 4y)dx = 0 A) Using only the notations followed in class, Find: M(x, y) = N(x, y) = ◆ Əx -= M(x,y) af ◆ Əy → Therefore, we can conclude that the DE is B) Find a function f(x, y) such that: af = N(x,y) ; ; xy+ f(x, y) = OM dy ON dx The solution of the IVP is then: f(x, y) = C) Consider the IVP: (4x + 6y)dy + (-2x + 4y)dx = 0 || . ◆ ( y(1) = 1
Transcribed Image Text:Work Problem 1, Consider the DE: (4x + 6y)dy + (-2x + 4y)dx = 0 A) Using only the notations followed in class, Find: M(x, y) = N(x, y) = ◆ Əx -= M(x,y) af ◆ Əy → Therefore, we can conclude that the DE is B) Find a function f(x, y) such that: af = N(x,y) ; ; xy+ f(x, y) = OM dy ON dx The solution of the IVP is then: f(x, y) = C) Consider the IVP: (4x + 6y)dy + (-2x + 4y)dx = 0 || . ◆ ( y(1) = 1
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