Write a C function that, given a square matrix of floats, finds the diagonal with maximum average value. The function should have the following prototype: Eloat matrMaxDiag (float M[DIM] (DIM], int n); vhere DIM is the size of the matrix, and n (n <= DIM) is the number of rows and columns that are actually used. The function calculates the average value of each diagonal, and then returns the maximum of such values. Example of execution: 1.0 2.0 3.0 4.0 5.0 1.0 3.0 4.0 5.0 2.0 2.0 2.0 2.0 -2.0 2.0 2.0 2.0 2.0 -2.0 5.0/1 5.0 1.1 2.2 3.3 -4.4 5.5 1.1 2.2 3.3 -4.4 5.5 * 2.0/2 = 1.0 2.2 2.2 -3.2 4.2 4.2 2.2 2.2 -3.2 4.2 4.2 10.5/3 = 3.5 1.8 -2.3 3.1 4.9 5.0 1.8 -2.3 3.1 4.9 5.0 3.8/4 0.95 15.5/5 = 3.1 1.8/1 = 1.8 -0.1/2 = 6.4/3 = 2.133 Max diag average: 5.0 5.9/4 = 1.475 -0.05
Write a C function that, given a square matrix of floats, finds the diagonal with maximum average value. The function should have the following prototype: Eloat matrMaxDiag (float M[DIM] (DIM], int n); vhere DIM is the size of the matrix, and n (n <= DIM) is the number of rows and columns that are actually used. The function calculates the average value of each diagonal, and then returns the maximum of such values. Example of execution: 1.0 2.0 3.0 4.0 5.0 1.0 3.0 4.0 5.0 2.0 2.0 2.0 2.0 -2.0 2.0 2.0 2.0 2.0 -2.0 5.0/1 5.0 1.1 2.2 3.3 -4.4 5.5 1.1 2.2 3.3 -4.4 5.5 * 2.0/2 = 1.0 2.2 2.2 -3.2 4.2 4.2 2.2 2.2 -3.2 4.2 4.2 10.5/3 = 3.5 1.8 -2.3 3.1 4.9 5.0 1.8 -2.3 3.1 4.9 5.0 3.8/4 0.95 15.5/5 = 3.1 1.8/1 = 1.8 -0.1/2 = 6.4/3 = 2.133 Max diag average: 5.0 5.9/4 = 1.475 -0.05
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![Write a C function that, given a square matrix of floats, finds the diagonal with maximum average value. The function should have the following prototype:
float matrMaxDiag (float M[DIM] [DIM], int n);
where DIM is the size of the matrix, and n (n <= DIM) is the number of rows and columns that are actually used.
The function calculates the average value of each diagonal, and then returns the maximum of such values.
Example of execution:
1.0
2.0
3.0
4.0
5.0
1.0
3.0
4.0
5.0
2.0
2.0
2.0
2.0
-2.0
2.0
2.0
2.0
2.0
-2.0
5.0/1 = 5.0
1.1
2.2
3.3
-4.4
5.5
1.1
2.2
3.3
-4.4
5.5
2.0/2 = 1.0
2.2
2.2
-3.2
4.2
4.2
2.2
2.2
-3.2
4.2
4.2
10.5/3 = 3.5
1.8
-2.3
3.1
4.9
5.0
1.8
-2.3
3.1
4.9
5.0
3.8/4 0.95
15.5/5 = 3.1
1.8/1 = 1.8 -0.1/2 = 6.4/3 =
2.133
Max diag average: 5.0
5.9/4 = 1.475
-0.05
A
Warning! We recommend using spaces instead of tabs for code indentation, since the TAB character is used for page navigation by the platform. If
necessary or useful, you can write other functions besides the required one(s).
float matrMaxDiag(float M[DIM][DIM], int n) {
}
|寸
|寸|
olo](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc0f1eb44-3cb8-4f9d-8a6b-6ec73b2c77d2%2F1cca7781-e244-4029-854e-15a2b3bfc55c%2Fjup48t_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Write a C function that, given a square matrix of floats, finds the diagonal with maximum average value. The function should have the following prototype:
float matrMaxDiag (float M[DIM] [DIM], int n);
where DIM is the size of the matrix, and n (n <= DIM) is the number of rows and columns that are actually used.
The function calculates the average value of each diagonal, and then returns the maximum of such values.
Example of execution:
1.0
2.0
3.0
4.0
5.0
1.0
3.0
4.0
5.0
2.0
2.0
2.0
2.0
-2.0
2.0
2.0
2.0
2.0
-2.0
5.0/1 = 5.0
1.1
2.2
3.3
-4.4
5.5
1.1
2.2
3.3
-4.4
5.5
2.0/2 = 1.0
2.2
2.2
-3.2
4.2
4.2
2.2
2.2
-3.2
4.2
4.2
10.5/3 = 3.5
1.8
-2.3
3.1
4.9
5.0
1.8
-2.3
3.1
4.9
5.0
3.8/4 0.95
15.5/5 = 3.1
1.8/1 = 1.8 -0.1/2 = 6.4/3 =
2.133
Max diag average: 5.0
5.9/4 = 1.475
-0.05
A
Warning! We recommend using spaces instead of tabs for code indentation, since the TAB character is used for page navigation by the platform. If
necessary or useful, you can write other functions besides the required one(s).
float matrMaxDiag(float M[DIM][DIM], int n) {
}
|寸
|寸|
olo
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