write a C++ program to combines the three summations and linear search algorithm to find the three summations of the M number. Do you think that by using this combination, there will be an improvement in the three summation algorithm performance? three summations 3-sum: brute-force algorithm Linear Search Algorithm publie elass Threedun • The linear search algorithm locates an item in a list by examining elements in the sequence one at a time, starting at the beginning. • First compare x with a, If they are equal, return the position 1. • If not, try a,. If x a, return the position 2. • Keep going, and if no match is found when the entire list is scanned, publie statie int count (intt] a) int Na.length: int count 0 for (int i 0:i
write a C++ program to combines the three summations and linear search algorithm to find the three summations of the M number. Do you think that by using this combination, there will be an improvement in the three summation algorithm performance? three summations 3-sum: brute-force algorithm Linear Search Algorithm publie elass Threedun • The linear search algorithm locates an item in a list by examining elements in the sequence one at a time, starting at the beginning. • First compare x with a, If they are equal, return the position 1. • If not, try a,. If x a, return the position 2. • Keep going, and if no match is found when the entire list is scanned, publie statie int count (intt] a) int Na.length: int count 0 for (int i 0:i
Computer Networking: A Top-Down Approach (7th Edition)
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Author:James Kurose, Keith Ross
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Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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![write a C++ program to combines the three summations and linear search algorithm to find the
three summations of the M number.
Do you think that by using this combination, there will be an improvement in the three
summation algorithm performance?
three summations
3-sum: brute-force algorithm
Linear Search Algorithm
publie elass Threesun
• The linear search algorithm locates an item in a list by examining elements in
the sequence one at a time, starting at the beginning.
• First compare x with a,. If they are equal, return the position 1.
• If not, try a,. Ifx a, return the position 2.
• Keep going, and if no match is found when the entire list is scanned,
publie static int count (int(] a)
int N-a.length:
int count 0:
for (int i = 0; i < N; 1++)
for (int j- i+1: j< N; 3++)
for (int k- j+1: k < N; k++)
if (a[4) + al31 + a[k] - 0)
return 0.
check each triple
+ for simplicity, ignore
integer overflow
procedure linear search(x:integer,
a,, a, .a,: distinct integers)
count++
return count:
i:=1
while (isnand x * a)
i:=i+1
if isn then location := i
else location := 0
return location{location is the subscript of the term that
equals x, or is 0 if x is not found}
publie statie void main (String() args)
int[) a- In.readints (arg= [0]) :
Stdout.printin (count (a)):](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F868ce835-2cd8-49b3-9103-4471a84a72fa%2F042e00b3-250d-4750-9682-bbb5ecf6a2ee%2Fra79txn_processed.jpeg&w=3840&q=75)
Transcribed Image Text:write a C++ program to combines the three summations and linear search algorithm to find the
three summations of the M number.
Do you think that by using this combination, there will be an improvement in the three
summation algorithm performance?
three summations
3-sum: brute-force algorithm
Linear Search Algorithm
publie elass Threesun
• The linear search algorithm locates an item in a list by examining elements in
the sequence one at a time, starting at the beginning.
• First compare x with a,. If they are equal, return the position 1.
• If not, try a,. Ifx a, return the position 2.
• Keep going, and if no match is found when the entire list is scanned,
publie static int count (int(] a)
int N-a.length:
int count 0:
for (int i = 0; i < N; 1++)
for (int j- i+1: j< N; 3++)
for (int k- j+1: k < N; k++)
if (a[4) + al31 + a[k] - 0)
return 0.
check each triple
+ for simplicity, ignore
integer overflow
procedure linear search(x:integer,
a,, a, .a,: distinct integers)
count++
return count:
i:=1
while (isnand x * a)
i:=i+1
if isn then location := i
else location := 0
return location{location is the subscript of the term that
equals x, or is 0 if x is not found}
publie statie void main (String() args)
int[) a- In.readints (arg= [0]) :
Stdout.printin (count (a)):
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