Write a C++ program to read N integers from user/keyboard and find the average of those N integers and print the result.
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- Rewrite the following C program using only system calls such as open, close, read, write, clear, loctl, etc. Don't use calls from C or C++ libraries uncluding cout, cin, printf, scanf, etc.Program #3: Write a small C program: reverse.c that: 5. Read an integer number from the command line using scanf( ). 6. Prints the number with its digits reversed to the screen. 7. Finish with value of 0.Please can you make a C program with this? With the file naming main.c matrix.h and matrix.c
- Here's my instructions for a C++ program. Can anyone help me? Write a program that mimics a calculator. The program should take as input: 1. The first integer 2. The second integer 3. The operation to be performed (+, -, *, /)It should then output the numbers, the operator, and the result. (For division, if the denominator is zero, output an appropriate message. The message should contain the word "error")Complete the C++ programs lastline.c and longestline.c, where each program should: - Take a single command-line argument representing the input file name, - Process the input file, and - Write to standard output4) Write a C program to input a random number in the range [1,10] and also input numbers from the user until the user entered number matches with the random number generated. In the output, print the number of guesses in which the user input matches with the entered number.
- Write a code using c programming to answer the following question. Write a C'+ program that receives two double values from the user. The program then should print the (addition), (subtraction), (multiplication), and (division).Can you convert this to basic c language? The output must be like the one on the photo #include <iostream> using namespace std; int main(){ char location[100] = "CodeChumIsLoveAndProgrammingAsWellYey"; int value=0; cout<<"Enter the address: "; cin >> value; cout << "Place at index " << value << " is " << location[value]; return 0;}