Write a local function Eq_Solve that will solve the (ax³+bx²+cx+1=0) equation with a variable number of input arguments (a, b, and c), and pass three outputs (x1, x2 and x3). Four cases should be considered: Case 1. If no Input arguments is passed, a =1; b=2; c=3; values are taken as inputs. Case 2. If one Input argument is passed, it should be a, and b=2; c=3 are taken as inputs. Case 3. If two Input arguments are passed, they should be a and b, c=3 is taken as a 3rd input Case 4. If three Input arguments are passed, they will be considered as a, b and c, respectively.

Find the minimum product of sums for the following function. Each drop down menu has a number of choices. You must select an answer from each drop down menu. The choices include possible terms in the function. Another choice is "none", and should be used when none of the terms from that drop down menu are needed for the minimum solution. Finally, the choice "two or more" should be selected if more than one of the possible terms appearing in that drop down menu are required for the solution. There are too many possible 3 and 4 literal terms for automatic checking, so just select how many of them are required. f(a,b,c,d) = m(0, 1, 2, 4, 5, 6, 12, 13) + Σd(8, 14) Terms involving a and b: [Select] Terms involving a and c: [Select] Terms involving a and d: [Select] Terms involving b and c: [Select] Terms involving b and d: [Select] Terms involving c and d: [Select] Terms involving 3 literals: [Select] Terms involving 4 literals: [Select] > >

Given main() and GVCoin struct, complete function Consecutive Heads() in main.c that counts and returns the number of flips taken to achieve a desired number of consecutive heads without a tails. Function ConsecutiveHeads() has a GVCoin struct and an integer representing the desired number of consecutive heads without a tails as parameters. Review the GVCoin struct in "GVCoin.h" and the function implementations in "GVCoin.c" by clicking on the orange arrow Note: For testing purposes, a GVCoin struct is created in the main() function using a pseudo-random number generator with a fixed seed value. The program uses a seed value of 15 during development, but when submitted, a different seed value will be used for each test case. Ex: If the GVCoin struct is created with a seed value of 15 and the desired number of consecutive heads is 5, then the function Consecutive Heads() returns 53 and the program outputs: Total number of flips for 5 consecutive heads: 53 LAB ACTIVITY 9.13.1: LAB:…

1. A set of integers are relatively prime to each other if there is no integer greater than 1 that divides all the elements. Furthermore, in Number Theory, it is known that the Euler function,ϕ (n), expresses the number of positive integers less than n that are relatively prime with n. Choose the alternative that has the correct value of ϕ(n) for every n below. A) ϕ(5) = 4 B) ϕ(6) = 2 C) ϕ(10) = 3 D) ϕ(14) = 6 E) ϕ(17) = 16

For all a and b in the domain of a function f, the function is injective iff f(a) #f(b) a=Db f(a)=f(b) a=b f(a)=f(b) atb o fly)=x iff f(x)=y A Moving to another question will save this response. 5

The greatest common divisor (GCD) for a pair of numbers is the largest positive integer that divides both numbers without remainder. For function GCD, write the missing base case condition and action. This function will compute the greatest common divisor of x and y. You can assume that x and y are both positive integers and that x > y. Greatest common divisor is computed as follows:GCD(x, 0) = x and GCD(x, y) = GCD(y, x % y). Examples: GCD(6, 4) -> 2 public int GCD(int x, int y) {  if <<Missing base case condition>> {    <<Missing base case action>>  } else {    return GCD(y, x % y);  }}

Solve the problems Solve the quadratic equation 2x^2 + 6x + 4 = 0. Implement a function that takes incoefficients A,B,and C forthequadratic equation Ax2 + Bx + C = 0 and computes the two solutions. Have the function return the number of valid (not NaN) solutions and fill in the return arguments so the smaller of the two solutions is first.