Write a loop that sets newScores to oldScores shifted once left, with element 0 copied to the end. Ex: If oldScores = {10, 20, 30, 40}, then newScores = {20, 30, 40, 10}. Note: These activities may test code with different test values. This activity will perform two tests, both with a 4-element array (int oldScores[4]). Also note: If the submitted code tries to access an invalid array element, such as newScores[9] for a 4-element array, the test may generate strange results. Or the test may crash and report "Program end never reached", in which case the system doesn't print the test case that caused the reported message. #include using namespace std; int main() { const int SCORES_SIZE = 4; int oldScores[SCORES_SIZE]; int newScores[SCORES_SIZE]; int i; for (i = 0; i < SCORES_SIZE; ++i) { cin >> oldScores[i]; } /* Your solution goes here */ for (i = 0; i < SCORES_SIZE; ++i) { cout << newScores[i] << " "; } cout << endl; return 0; }

Write a loop that sets newScores to oldScores shifted once left, with element 0 copied to the end. Ex: If oldScores = {10, 20, 30, 40}, then newScores = {20, 30, 40, 10}. Note: These activities may test code with different test values. This activity will perform two tests, both with a 4-element array (int oldScores[4]). Also note: If the submitted code tries to access an invalid array element, such as newScores[9] for a 4-element array, the test may generate strange results. Or the test may crash and report "Program end never reached", in which case the system doesn't print the test case that caused the reported message. #include using namespace std; int main() { const int SCORES_SIZE = 4; int oldScores[SCORES_SIZE]; int newScores[SCORES_SIZE]; int i; for (i = 0; i < SCORES_SIZE; ++i) { cin >> oldScores[i]; } /* Your solution goes here */ for (i = 0; i < SCORES_SIZE; ++i) { cout << newScores[i] << " "; } cout << endl; return 0; }

C++ Programming: From Problem Analysis to Program Design

8th Edition

ISBN:9781337102087

Author:D. S. Malik

Publisher:D. S. Malik

Chapter12: Points, Classes, Virtual Functions And Abstract Classes

Section: Chapter Questions

Problem 29SA

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Write a loop that sets newScores to oldScores shifted once left, with element 0 copied to the end. Ex: If oldScores = {10, 20, 30, 40}, then newScores = {20, 30, 40, 10}.Note: These activities may test code with different test values. This activity will perform two tests, both with a 4-element array (int oldScores[4]). See "How to Use zyBooks".Also note: If the submitted code tries to access an invalid array element, such as newScores[9] for a 4-element array, the test may generate strange results. Or the test may crash and report "Program end never reached", in which case the system doesn't print the test case that caused the reported message. #include <iostream>using namespace std; int main() {const int SCORES_SIZE = 4;int oldScores[SCORES_SIZE];int newScores[SCORES_SIZE];int i; for (i = 0; i < SCORES_SIZE; ++i) {cin >> oldScores[i];} /* Your solution goes here */ for (i = 0; i < SCORES_SIZE; ++i) {cout << newScores[i] << " ";}cout << endl; return…
Write a loop that sets newScores to oldScores shifted once left, with element 0 copied to the end. Ex: If oldScores = {10, 20, 30, 40}, then newScores = {20, 30, 40, 10}.Note: These activities may test code with different test values. This activity will perform two tests, both with a 4-element array (int oldScores[4]). See "How to Use zyBooks".Also note: If the submitted code tries to access an invalid array element, such as newScores[9] for a 4-element array, the test may generate strange results. Or the test may crash and report "Program end never reached", in which case the system doesn't print the test case that caused the reported message. import java.util.Scanner; public class StudentScores { public static void main (String [] args) { Scanner scnr = new Scanner(System.in); final int SCORES_SIZE = 4; int[] oldScores = new int[SCORES_SIZE]; int[] newScores = new int[SCORES_SIZE]; int i; for (i = 0; i < oldScores.length; ++i) { oldScores[i] = scnr.nextInt(); } for (i = 0; i…
Write a for loop to print all elements in courseGrades, following each element with a space (including the last). Print forwards, then backwards. End each loop with a newline. Ex: If courseGrades = {7, 9, 11, 10}, print:7 9 11 10 10 11 9 7 Hint: Use two for loops. Second loop starts with i = NUM_VALS - 1. Note: These activities may test code with different test values. This activity will perform two tests, both with a 4-element array (int courseGrades[4]). Also note: If the submitted code tries to access an invalid array element, such as courseGrades[9] for a 4-element array, the test may generate strange results. Or the test may crash and report "Program end never reached", in which case the system doesn't print the test case that caused the reported message. #include <iostream>using namespace std; int main() { const int NUM_VALS = 4; int courseGrades[NUM_VALS]; int i; for (i = 0; i < NUM_VALS; ++i) { cin >> courseGrades[i]; } /* Your solution goes…
Write a hangman game that randomly generates a word andprompts the user to guess one letter at a time, as presented in the sample run.Each letter in the word is displayed as an asterisk. When the user makes a correctguess, the actual letter is then displayed. When the user finishes a word, displaythe number of misses and ask the user whether to continue to play with anotherword. Declare an array to store words, as follows:// Add any words you wish in this arrayString[] words = {"write", "that",...}; (Guess) Enter a letter in word ******* > p↵Enter(Guess) Enter a letter in word p****** > r↵Enter(Guess) Enter a letter in word pr**r** > p↵Enterp is already in the word(Guess) Enter a letter in word pr**r** > o↵Enter(Guess) Enter a letter in word pro*r** > g↵Enter(Guess) Enter a letter in word progr** > n↵Entern is not in the word(Guess) Enter a letter in word progr** > m↵Enter(Guess) Enter a letter in word progr*m > a↵EnterThe word is program. You missed 1 timeDo…
Instrument shellsort to print the number of compares divided by the array sizefor each increment. Write a test client that tests the hypothesis that this number is asmall constant, by sorting arrays of random Double values, using array sizes that areincreasing powers of 10, starting at 100
Consider the following code segment that includes a method called multiply. The multiply method is a sample method for the multiplication of an n by m array and an m by p array. Suppose the multiply method is invoked as shown, what will be the value of the expressiona5[1][1]?Note that the initializeArray method puts a 0 to every cell of the array passed to initializeArray.
You are given an array-like data structure Listy which lacks a size method. It does, however, have an elementAt ( i) method that returns the element at index i in 0( 1) time. If i is beyond the bounds of the data structure, it returns -1. (For this reason, the data structure only supports positive integers.) Given a Listy which contains sorted, positive integers, find the index at which an element x occurs. If x occurs multiple times, you may return any index. Write code with explanation
How can you remove all objects of the same type from a custom-built array? I cannot use predefined methods such as remove() I have to use a for loop to search for the object and remove it from the array while returning the number of objects that were removed. I also need to remove just the first instance of this object and return true if removed, false if the object is not in the array. /** * Removes all instances of this object from the list. * * @param obj the object to match for removal * @return the number of objects removed */ int removeAll(GenClass obj) {
C++ help Write a loop that sets newScores to oldScores shifted once left, with element 0 copied to the end. Ex: If oldScores = {10, 20, 30, 40}, then newScores = {20, 30, 40, 10}.Note: These activities may test code with different test values. This activity will perform two tests, both with a 4-element array (int oldScores[4]). Also note: If the submitted code tries to access an invalid array element, such as newScores[9] for a 4-element array, the test may generate strange results. Or the test may crash and report "Program end never reached", in which case the system doesn't print the test case that caused the reported message. code provided to use: #include <iostream>using namespace std; int main() { const int SCORES_SIZE = 4; int oldScores[SCORES_SIZE]; int newScores[SCORES_SIZE]; int i; for (i = 0; i < SCORES_SIZE; ++i) { cin >> oldScores[i]; } /* Your solution goes here */ for (i = 0; i < SCORES_SIZE; ++i) { cout <<…
Write method findZero, as started below. findZero should return the index of the first element of array A that contains the value zero, starting from position 0 up through position pos. If no element of A from position 0 to position pos contains the value zero, then findZero should return –1. For example: Array (A) Position (pos) Value returned by findZero(A, pos) 1 0 2 5 6 0 -1 1 0 2 5 6 1 1 1 0 2 5 6 2 1 1 0 2 0 6 2 1 1 0 2 0 6 4 1 1 2 3 4 5 4 -1 Complete method findZero below. Assume that it is called only with values that satisfy its assumptions as stated below. // Description: Returns smallest index k // such that (0 <= k <= pos) and (A[k] == 0) // Assumptions: 0 <= pos < A.length public int findZero(int[] A, int pos) {
given an array of integer values , return true if 6 appears as either the first or last element in the array. firstLast6([1,2,36]) true firstLast([6,1,2,3]) true firstLast([13,6,1,2,3]) false
In the following code both myList and yourList are dynamic arrays of the same size. The code initializes the array myList to certain values. The value in each element of yourList should be twice the value in the corresponding element in myList. However, the output of this code would show that is not the case. Provide the correct code to accomplish the desired results. int *myList;int *yourList;myList = new int[5];myList[0] = 8;for (int i = 1; i < 5; i++)myList[i] = i * myList[i - 1];yourList = myList;for (int i = 0; i < 5; i++)yourList[i] = 2 * myList[i];