Write a MATLAB code for computing the following functions in one program: x ≥ 2 and y = 0.5 x210 and y<8 Else Z Z= 1 2пу X e-y/2x In(y) √x w = sin(x) = √x + √y Z= w=lnx-3lny
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- Define a function CalculatePyramidVolume with inputs baseLength, baseWidth, and pyramidHeight. The function returns pyramidVolume, the volume of a pyramid with a rectangular base. Hint: Recall that a function declaration begins with function'. Pay attention to the spelling and character case of variables. Ex: pyramidvalue and pyramidValue are different variables. Relevant geometry equation: pyramidVolume = baseLength * baseWidth * pyramidHeight * 1/3Write a MATLAB function called “function1” to calculate the value of y for a given input value of x: If the value of x is greater than 0 and less than 5, then y = 3x If the value of x is less than or equal to 0, then y = -4x If the value of x is greater than or equal to 5, then y = 15Computer Science Write octave program which simulates the motion of fall and bounce of pencil in the floor? Where the coefficient friction= 0.5, pencil mass = 10g The distance from the center of mass to the bottom end of the pencil= 0.1m Theat0= 1 #Use ode function
- Define a function calc_pyramid_volume() with parameters base_length, base_width, and pyramid_height, that returns the volume of a pyramid with a rectangular base. calc_pyramid_volume() calls the given calc_base_area() function in the calculation.Relevant geometry equations:Volume = base area x height x 1/3(Watch out for integer division).Sample output with inputs: 4.5 2.1 3.0 Volume for 4.5, 2.1, 3.0 is: 9.45 def calc_base_area(base_length, base_width): return base_length * base_width ''' Your solution goes here ''' length = float(input())width = float(input())height = float(input())print('Volume for', length, width, height, "is:", calc_pyramid_volume(length, width, height))Write a function print_shampoo_instructions() with parameter num_cycles. If num_cycles is less than 1, print "Too few.". If more than 4, print "Too many.". Else, print "N : Lather and rinse." num_cycles times, where N is the cycle number, followed by "Done.".Sample output with input: 2 1 : Lather and rinse. 2 : Lather and rinse. Done. Hint: Define and use a loop variable. I have to define a "print_shampoo_instruction" function def shampoo_instructions(num_cycles): if num_cycles < 1: print('Too few.') elif num_cycles > 4: print('Too many.') else: i = 0 while i<num_cycles: print(i + 1,": Lather and rinse.") i = i + 1 print('Done.') def print_shampoo_instructions(num_cycles): print(shampoo_instructions(num_cycles)) return num_cycles ## this is my code user_cycles = int(input())#can not be alter in the programprint_shampoo_instructions(user_cycles)#can not be alter in the program(Python) Define a function calc_pyramid_volume() with parameters base_length, base_width, and pyramid_height, that returns the volume of a pyramid with a rectangular base. calc_pyramid_volume() calls the given calc_base_area() function in the calculation.Relevant geometry equations:Volume = base area x height x 1/3(Watch out for integer division).Sample output with inputs: 4.5 2.1 3.0Volume for 4.5, 2.1, 3.0 is: 9.45
- Numbers can be regarded as product of its factors. For example,8 = 2 x 2 x 2; = 2 x 4.Write a function that takes an integer n and return all possible combinationsof its factors.Numbers can be regarded as product of its factors. For example,8 = 2 x 2 x 2; = 2 x 4.Examples:input: 1output:[]input: 37output:[]input: 32output:[ [2, 16], [2, 2, 8], [2, 2, 2, 4], [2, 2, 2, 2, 2],""".Define a Racket function that takes a numerical value as input and returns the value defined by the expression n2 - (n - 1)2CHALLENGE ACTIVITY 6.1.5: Function definition: Volume of a pyramid. Define a function calc_pyramid_volume with parameters base_length, base_width, and pyramid_height, that returns the volume of a pyramid with a rectangular base.Sample output with inputs: 4.5 2.1 3.0 Volume for 4.5, 2.1, 3.0 is: 9.45 Relevant geometry equations:Volume = base area x height x 1/3Base area = base length x base width. Use Python, please.
- Write a MATLAB function to calculate the volume of a Cone. Use the following equation: V= (1/3) Thr^2 Then call this function in a for loop that calculates the volume of five Cones. Where the Cone Heights are h= {5, 8, 7, 11,9} cm, and its radius r= {6, 10, 9, 8, 4} cm respectively, then display the results.Numbers can be regarded as product of its factors. For example,8 = 2 x 2 x 2; = 2 x 4.Write a function that takes an integer nand return all possible combinations of its factors.Note:You may assume that n is always positive.Factors should be greater than 1 and less than n.Examples:input: 1output:[]input: 37output:[]input: 12output:[ [2, 6], [2, 2, 3], [3, 4]]input: 32output:[ [2, 16], [2, 2, 8], [2, 2, 2, 4], [2, 2, 2, 2, 2], [2, 4, 4], [4, 8]].Define a function calc_pyramid_volume() with parameters base_length, base_width, and pyramid_height, that returns the volume of a pyramid with a rectangular base. calc_pyramid_volume() calls the given calc_base_area() function in the calculation.Relevant geometry equations:Volume = base area x height x 1/3(Watch out for integer division).Sample output with inputs: 4.5 2.1 3.0 Volume for 4.5, 2.1, 3.0 is: 9.45 python def calc_base_area(base_length, base_width): return base_length * base_width ''' Your solution goes here ''' length = float(input())width = float(input())height = float(input())print('Volume for', length, width, height, "is:", calc_pyramid_volume(length, width, height))