Write a program that takes in four positive integers and outputs the number of odd numbers. (Hint: use the modulo operator to determine if a number is odd) Ex: If the input is: 1 2 3 4 the output is: 2 Below is my code so far and I'm getting back unexpected EOF while parsing. I can't figure out what I'm doing wrong. odd_number=[] number_1=int(input()) number_2=int(input()) number_3=int(input()) number_4=int(input()) if number_1%2!=0:     odd_number.append(number_1) else:     pass if number_2%2!=0:     odd_number.append(number_2) else:     pass if number_3%2!=0:     odd_number.append(number_3) else:     pass if number_4%2!=0:     odd_number.append(number_4) else:     pass print(len(odd_number)

C++ Programming: From Problem Analysis to Program Design
8th Edition
ISBN:9781337102087
Author:D. S. Malik
Publisher:D. S. Malik
Chapter5: Control Structures Ii (repetition)
Section: Chapter Questions
Problem 14PE
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Write a program that takes in four positive integers and outputs the number of odd numbers. (Hint: use the modulo operator to determine if a number is odd)

Ex: If the input is:

1 2 3 4

the output is:

2

Below is my code so far and I'm getting back unexpected EOF while parsing. I can't figure out what I'm doing wrong.

odd_number=[]
number_1=int(input())
number_2=int(input())
number_3=int(input())
number_4=int(input())
if number_1%2!=0:
    odd_number.append(number_1)
else:
    pass
if number_2%2!=0:
    odd_number.append(number_2)
else:
    pass
if number_3%2!=0:
    odd_number.append(number_3)
else:
    pass
if number_4%2!=0:
    odd_number.append(number_4)
else:
    pass
print(len(odd_number)

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