Write a program that tells what coins to give out for any amount of change from 1 cent to 99 cents. For example, if the amount is 86 cents, the output would be something like the following: 86 cents can be given as 3 quarter(s) 1 dime(s) and 1 penny(pennies) Use coin denominations of 25 cents (quarters), 10 cents (dimes), and 1 cent (pennies). Do not use nickel and half-dollar coins. Your program will use the following function (among others): void computeCoins(int coinValue, int& num, int& amountLeft); //Precondition: 0 < coinValue < 100; 0 <= amountLeft < 100. //Postcondition: num has been set equal to the maximum number //of coins of denomination coinValue cents that can be obtained //from amountLeft. Additionally, amountLeft has been decreased //by the value of the coins, that is, decreased by //num * coinValue For example, suppose the value of the variable amountLeft is 86. Then, after the following call, the value of number will be 3 and the value of amountLeft will be 11 (because if you take 3 quarters from 86 cents, that leaves 11 cents): computeCoins(25, number, amountLeft); Include a loop that lets the user repeat this computation for new input values until the user says he or she wants to end the program. (Hint: Use integer division and the % operator to implement this function.)
Write a
from 1 cent to 99 cents. For example, if the amount is 86 cents, the output
would be something like the following:
86 cents can be given as
3 quarter(s) 1 dime(s) and 1 penny(pennies)
Use coin denominations of 25 cents (quarters), 10 cents (dimes), and
1 cent (pennies). Do not use nickel and half-dollar coins. Your program
will use the following function (among others):
void computeCoins(int coinValue, int& num, int& amountLeft);
//Precondition: 0 < coinValue < 100; 0 <= amountLeft < 100.
//Postcondition: num has been set equal to the maximum number
//of coins of denomination coinValue cents that can be obtained
//from amountLeft. Additionally, amountLeft has been decreased
//by the value of the coins, that is, decreased by
//num * coinValue
For example, suppose the value of the variable amountLeft is 86. Then,
after the following call, the value of number will be 3 and the value of
amountLeft will be 11 (because if you take 3 quarters from 86 cents, that
leaves 11 cents):
computeCoins(25, number, amountLeft);
Include a loop that lets the user repeat this computation for new input
values until the user says he or she wants to end the program. (Hint: Use
integer division and the % operator to implement this function.)
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