Write a program to compute a^n (a power n) using recursion. Note: Refer to the problem requirements. Shell Scripting Function Specifications: Use the function name as computePower() and the 2 integer arguments. This function returns an integer value that is 'a power n' Function specification: int computePower(int a,int n) Input and Output Format: Input consists of 2 integers. The output is the a power n. Refer sample input and output for formatting specifications. Sample Input and Output: [All text in bold corresponds to input and the rest corresponds to output.] Enter the value of a Enter the value of n 8 The value of 2 power 8 is 256 Function Definitions: int computePower (int,int) Problem Requirements: Keyword Min Count Маx Count for Keyword Min Count Max Count while .

Write a program to compute a^n (a power n) using recursion. Note: Refer to the problem requirements. Shell Scripting Function Specifications: Use the function name as computePower() and the 2 integer arguments. This function returns an integer value that is 'a power n' Function specification: int computePower(int a,int n) Input and Output Format: Input consists of 2 integers. The output is the a power n. Refer sample input and output for formatting specifications. Sample Input and Output: [All text in bold corresponds to input and the rest corresponds to output.] Enter the value of a Enter the value of n 8 The value of 2 power 8 is 256 Function Definitions: int computePower (int,int) Problem Requirements: Keyword Min Count Маx Count for Keyword Min Count Max Count while .

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Write a shell scripting program to find the number of digits in a number using recursion.Note:Refer to the problem requirements.Shell Scripting Function Specifications:Use the function name as computeNumber() and an integer argument.This function returns the number of digits in the input.Function specification:int computeNumber(int n) Input and Output Format: Input consists of a non-negative integer. Refer sample input and output for formatting specifications. [All text in bold corresponds to input and the rest corresponds to output.] Sample Input and Output:Enter the value of n432 The number of digits in 432 is 3 Problem Requirements: DON'T USE FOR LOOP AND WHILE LOOP IN YOUR SOLUTION. Function Definitions: int computeNumber (int)
Consider the following recursive function: void recurse(int num) { if (num == 0) cout << “ Zero” << endl; else { cout << " " << num << " " << endl; recurse(num + 1) } } Is recurse (-2) a valid call? If a valid call, what is the output of the entire function execution? If not a valid call, explain why it is not a valid call.
Consider the following recursive function: void recurse(int num) { if (num == 0) cout << “ Zero” << endl; else { cout << " " << num << " " << endl; recurse(num + 1) } } Is recurse (8) a valid call? If a valid call, what does the function output? If not a valid call, explain why it is not a valid call.
Please answer it in Python Write a double_consonant function , It takes a word as a parameter and has two return values ： A Boolean value equals True If the word contains a double consonant （ The same consonant twice in a row ）, under these circumstances , The second value returned is the double consonant ; If there are no double consonants , Function should return False and None. relevant information ： To simplify the exercise , We don't use words that contain multiple double consonants （ for example ,“successor”） Test your functionality on . Example ： double_consonne('arrivee') vaut True, 'r'.double_consonne('bonbon') vaut False, Nonedouble_consonne('reussite') vaut True, 's'
1.The following is the C code that you need to implement for this lab: uint8_ t f(uint8_tn) return(n<2)?(n):(f(n-1)+f(n-2)); The main function can be assumed as follows: int main() uint8_ t x; x=f(???); return 0; Obviously, " ? ? ? " is representing a value used to test the algorithm! Is "f"recursive? a.No answer text provided. b.Yes c.no d.depends on whether it is in for main 2.First, make the code in the previous question an actual C program so that it can be compiled and it runs. Play with it so that you feel comfortable with the logic of the code. Then implement the code in TTPASM. Note that you need to preserve the actual C code structure, this means you cannot it into a non-recursive subroutine. Furthermoreall conventions discussed in class regarding subroutines must be followed. The idea is that I should be able to substitute f with my own code, and main should work. Or, I can substitute main with my own, and f should work. Attach the source code of your assembly…
Write a code Using Pointers that can print a table of values for coordinatepoints (x,y) for a given expressiona. Your code should be able to calculate the function values of typey=mx+cb. Ask the user to give input of m and c. Use pointersc. Ask the user to input how many data points of the function he wants togenerate. Use pointersd. Then dynamically allocate memory for those data pointse. Take input for the x coordinates and store them in the allocateddynamic memory using pointers.f. Calculate the corresponding y values and store them in anotherdynamically allocated memory array.g. Print the data points (x and y) in a tabular form. Use pointers.
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Write program in python with a function occupy(n), which shows how birds are going to occupy n nests, assuming that each new bird will choose the nest in the middle of the largest unoccupied run of nests. For example, if there were 10 nests, occupy(10) would print out the following sequence, where underscore indicates an unoccupied nest, and X indicates an occupied nest. The first line of the printout is just 10 underscores showing that all the nests are unoccupied. The second line shows that a bird came to nest in position 5, since that is one the first middle positions of the unoccupied run from 0 to 9. In the third line a bird came to occupy the middle position for the longest open run of nests, from 0 to index 4.
12. Consider the recursive function int gcd( int a, int b) int gcd( int a, int b){ if (b > a) return gcd(b,a); if ( b == 0 ) return a; return gcd( b, a% b); } How many invocation (calls) of the gcd() function will be made by the call gcd(72, 30)?
The goal is to rewrite the function, below, such that passes in a different list of parameters, particularly eliminating the need to pass low and high for each recursive call to binary_search. defbinary_search(nums,low,high,item): mid=(low+high)//2iflow>high:returnFalse #The item doesn't exist in the list!elifnums[mid]==item:returnTrue# The item exists in the list!elifitem<nums[mid]:returnbinary_search(nums,low,mid-1,item)else:returnbinary_search(nums,mid+1,high,item) The new function should be prototyped below. The number of changes between the given version, and the one requested is not significant. defbinary_search(nums,item):pass# Remove this and fill in with your code Tip: If you consider that high and low are used to create a smaller version of our problem to be processed recursively, the version requested will do the same thing, just through a different, more Pythonic technique.
C/C++ & MIPS The function ?add(?,?) for two positive integers 0≤?, and 0≤?, is defined as the following:?add(?,0)=?; ?add(?,?)=?add(?,?−1)Write a recursive version of ?add() in C or C++, then use this program to develop a MIPSprogram that gets as input two integers 0<? ≤255, and 0<? ≤255, and returns theresult of ?add(?,?) in $v1.Your deliverable should be the C/C++ code and the MIPS assembly function-code
In C, write a function that gets 3 pointers int* a, int* b, int* c, and rotates the values in their addresses to the left. That is, a gets the value of b, b gets the value of c, and c gets the value of a. void rotate3 (int* a, int* b, int* c); For example, if we have int x=1, y=2, z=3, then after calling rotate3 (&x, &y, &z) we should have x==2, y==3, and z==1. if we have int x=7, y=1, z=6, then after calling rotate3 (&x, &y, &z) we should have x==1, y==6, and z==7.