Write an equation for a circle given the following information. Center(12 , -3) containing the point (-12 , 7) O (x+ 12) + (y – 3) = 169 O (x + 12) + (y – 3) = 13 - o (x - 12) + (y + 3)' = 26 o (x – 12) + (y + 3)² = 676 11 12

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A: Standard equation of a circle with center (h,k) and radius r is              x - h2 + y - k2 = r2

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A: find the center of circle if it is helpful, please thumbs up or appericiate.

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Q: Find the equation of the circle that passes through the origin and has its center at (-4, 3).

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A: The solution as follows :-

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Q: a) Find the equation of the circle with center at (-2, 4) and passing through (5,-3). b) Write the…

A: Part a,Given,         An equation of the circle with center at -2,4 and passing through 5,-3.

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A: To Determine: Find the center and radius of the circle with equation :

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A: Given Ellipse: 21x2-4y2+84x-24y=36This equation can be re-written as-21(x2+4x)-4(y2+6y)=36 To find…

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A: Please refer the attached image for complete solution.

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Q: Find the center and radius of the circle 8x2+8y2-20x+64y-371=0. Then graph the circle.

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