-write sin*6X in terms of the first power of cosine.

Q: Write sin 2x - sin 5x as a product of trigonometric functions.

A:

Q: Express cos(tan-(2x + 3)) in an algebraic form.

A:

Q: 1 Evaluate | -1) – 1) sinx(2cosx -

A:

Q: Write sin*x + cosx in terms of first powers of cosine.

A: Given, sin4x+cos2x

Q: If /3tan0=3sin0,find the value of sin*0-cos²0

A:

Q: Find sin 5pai/6.

A:

Q: Complete the identity. sin'x (cscx+ se2x) = sec2x X. CS sec-x

A: To show: sin2x(csc2x+sec2x)=sec2x Solution: Considering LHS sin2x(csc2x+sec2x) On simplifying…

Q: Find the value of x sin 6x +sin6/3x -1 -1

A:

Q: Evaluate without using a calculator.      sin  (sin    -1 3/5)

A: It is known that sinsin-1x=x.

Q: Calculate sin 2i

A: We have to calculate the value of sin(2i)

Q: Simplify cos2(15)-sin2(15)

A:

Q: Find cos(θ-π/2) if sin θ=-0.57

A:

Q: 3 Tt Simplify sin (sinx) if TSXS . 2 -x-

A: Given : y=f(x)=sin^-1(sinx)

Q: Suppose a = 2 tan a. Rewrite in terms of sines and cosines: 1 x² + 4

A: Given x=2 tan a To simplify 1x2+4

Q: -sin 0+2sin0+3=4

A:

Q: Write ( tan(x) + sec(x)) ( sin( x) - 1) in terms of sine and cosine.

A:

Q: 1. sin62° =

A:

Q: If sinx^2 =a/b find cos(90-x)

A: See the details solution in below I am consider  sin(x^2 )

Q: Evaluate: " sin' (;) 4 .2

A: Evaluate :     ∫0πsin7x2cos4x2dx

Q: Evaluate V1 – sin 4xdx

A: Solve the given integral

Q: Simplify sin x (1-cosx)(1+cosx)

A:

Q: IT – sin 8. 2 Simplify cos - 8.

A: Given: (1)   cos2π8-sin2π8 (2)  2sin13∘ cos13∘

Q: Evaluate  ∫ππsin2x Cos4x dx .

A: Since the upper limit = the lower limit  So the value of the function will be 0

Q: if sin= -2/3 find csc ?.

A: We have to find value

Q: evaluate sin[cos-1(-1/2) - sin -1(1/2)]

A:

Q: Is sin2(0+1) zero or one?  Please explain

A:

Q: Find sin 0.

A:

Q: Express as a product.sin 3t - sin 7t

A: Given : sin 3t - sin 7t

Q: Write cos 3x cos 2x - sin 3x sin 2x as a single cosine.

A: Given expression is cos3xcos2x-sin3xsin2x. To write the given expression as a single cosine. We know…

Q: (a) Find the greatest and smallest values of 3-5 sinx.

A:

Q: Evaluate: " sin7 cos4 dx

A:

Q: Evaluate sin (5x) dx.

A: We have to find the given integration. We will do this integration by using substitution.

Q: Rewrite the product sin 5x sin 2x as a sum

A:

Q: Write sin(3x) + sin (7x) as a product of sines and/or cosines.

A: Given sin(3x) + sin (7x)  To Write  as a product of sines and/or cosines

Q: Find sin a. (-/5 ,2) [ ?] 1

A:

Q: Write the exact form:  sec(2x) if sin(x)=2/5

A: We need to evaluate the value of sec2x if sinx = 25

Q: Use the power reducing formulas to rewrite sin24x cos24x in terms of the first power of cosine.…

A:

Q: Find sin 20

A:

Q: Which of the products below is equivalent to sin (6x) – sin (4x)?

A: We use the basic trigonometric formulas to find the equivalent relation to the given expression.

Q: Write the expression as a single trigonometric fund cos 2x cos 8x - sin 2x sin 8x

A: We have the expression as cos 2x cos 8x -sin 2x sin 8x

Q: Express cos4t in terms of values of the cosine function with exponent 1

A: Given,         cos4t

Q: Write the expression in terms of sine only. 3 sin 7xx + 3V3 cos 7Rx

A: given =3sin7πx+33cos7πxr=32+(33)2=6rewrite expression as=6(36sin7πx+336cos7πx)=6(12sin7πx+32cos7πx)

Q: Use the formulas for lowering powers to rewrite the expression in terms of the first power of…

A: Write sin6x as sin2x3 and write it in terms of cosine and simplify. sin6x=sin2x3=1-cos 2x23

Q: Write the expression in terms of sine only. 3 sin(5πx) + 3sqrt3 cos(5πx)

A: Given expression can be written as Multiplying and dividing by 2, we get

Q: 5. Write sin 33° in terms of cosine.

A:

Q: Write sin^4 x in terms of first powers of cosine.

A: Given: Now using identities:

Q: sin 2x 2x +x

A: We have to find the limit of: L=limx→0sin 2x2x2+x

Q: Find sin(sin ), if n<0< Select one: Ө — п

A: To find sin-1(sin θ), if π&lt;θ&lt;3π2

Q: do 2 – sin(0)

A: Here we use substitution.

Q: Perform the Multiplication (sinx+cosx)^2

A: We can just perform the multiplication and trignometrical property.