Write the scalar equation of the plane with normal vector = [0,-1, 3] and passing through the point (5, -2, 3). a. y 3z +11=0 b. y 3z-11-0 c. d. -y+ 3z + 11 = 0 -y+ 3z + 16 = 0
Write the scalar equation of the plane with normal vector = [0,-1, 3] and passing through the point (5, -2, 3). a. y 3z +11=0 b. y 3z-11-0 c. d. -y+ 3z + 11 = 0 -y+ 3z + 16 = 0
Algebra and Trigonometry (MindTap Course List)
4th Edition
ISBN:9781305071742
Author:James Stewart, Lothar Redlin, Saleem Watson
Publisher:James Stewart, Lothar Redlin, Saleem Watson
Chapter8: Polar Coordinates And Parametric Equations
Section8.CT: Chapter Test
Problem 8CT
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![2. Write the scalar equation of the plane with normal vector = [0,-1, 3] and passing through the point (5,
-2, 3).
a. y 3z + 11 = 0
b.
y-3z-11=0
c.
d.
-y+ 3z + 11 = 0
-y+ 3z + 16 = 0](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F70562eea-c2fb-4751-9e42-c7c37c89fd29%2F87a00b31-4268-48a7-a1a0-f3a1647a66b0%2Fqdaflvd_processed.png&w=3840&q=75)
Transcribed Image Text:2. Write the scalar equation of the plane with normal vector = [0,-1, 3] and passing through the point (5,
-2, 3).
a. y 3z + 11 = 0
b.
y-3z-11=0
c.
d.
-y+ 3z + 11 = 0
-y+ 3z + 16 = 0
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