Write the scalar equation of the plane with normal vector = [0,-1, 3] and passing through the point (5, -2, 3). a. y 3z +11=0 b. y 3z-11-0 c. d. -y+ 3z + 11 = 0 -y+ 3z + 16 = 0

Algebra and Trigonometry (MindTap Course List)
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Chapter8: Polar Coordinates And Parametric Equations
Section8.CT: Chapter Test
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2. Write the scalar equation of the plane with normal vector = [0,-1, 3] and passing through the point (5,
-2, 3).
a. y 3z + 11 = 0
b.
y-3z-11=0
c.
d.
-y+ 3z + 11 = 0
-y+ 3z + 16 = 0
Transcribed Image Text:2. Write the scalar equation of the plane with normal vector = [0,-1, 3] and passing through the point (5, -2, 3). a. y 3z + 11 = 0 b. y-3z-11=0 c. d. -y+ 3z + 11 = 0 -y+ 3z + 16 = 0
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