Write the scalar equation of the plane with normal vector i - [1, 2, 1] and passing through thepoint (3, 2, 1).a) x+ 2y+z-8- 0b) 3x + 2y +z+ 8 = Oc) 3x + 2y +z-8 - 0d) x+ 2y +z+8 - 0Write the scalar equation of the piane with normal vector = [1, -1, 1] and having an x-intercept7.a) 7x- 7y+ 7z-7-0b) x-y+z+7-0c) x-y+z-7=0d) 7x-y+z-7-0

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Write the scalar equation of the plane with normal vector - [1, 2, 1] and passing through the point (3, 2, 1). a) x+ 2y+z-8 = 0 b) 3x+ 2y +z+ 8 = 0 c) 3x + 2y +z-8- 0 O d) x+ 2y +z+ 8 -0 Write the scalar equation of the plane with normal vector ā = [1, -1, 1] and having an x-intercept 7. a) Tx- Ty+ 7z-7-0 O b) x-y+z+7= 0 c) x-y+2-7-0 d) 7x-y+2-7-0

Write the scalar equation of the plane with normal vector - [1, 2, 1] and passing through the point (3, 2, 1). a) x+ 2y+z-8 = 0 b) 3x+ 2y +z+ 8 = 0 c) 3x + 2y +z-8- 0 O d) x+ 2y +z+ 8 -0 Write the scalar equation of the plane with normal vector ā = [1, -1, 1] and having an x-intercept 7. a) Tx- Ty+ 7z-7-0 O b) x-y+z+7= 0 c) x-y+2-7-0 d) 7x-y+2-7-0

Algebra & Trigonometry with Analytic Geometry

13th Edition

ISBN:9781133382119

Author:Swokowski

Publisher:Swokowski

Chapter8: Applications Of Trigonometry

Section8.4: The Dot Product

Problem 10E

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