In WW2, allies have placed their mines on the ground which can be considered as a gird of size N*M. Rows are numbered by integers from 1 to N and columns are numbered by integers from 1 to M. Each cell (i,j) has a mine in it if (itj) is divisible by 2. All the other cells are empty. Two cells are neighbours if they share a boundary or a corner. Your aim is to move from the first row to the last row using some special rules that the automatic mine placing system follows. The mines won't blow if the following rules are followed:

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In WW2, allies have placed their mines on the ground which can be considered
as a gird of size N*M. Rows are numbered by integers from 1 to N and columns
are numbered by integers from 1 to M. Each cell (i,j) has a mine in it if (i+j) is
divisible by 2. All the other cells are empty.
Two cells are neighbours if they share a boundary or a corner. Your aim is to
move from the first row to the last row using some special rules that the
automatic mine placing system follows. The mines won't blow if the following
rules are followed:
• If your current row number is odd, from a 'mined' cell (i.e. cell having a
mine in it) you can move only to a neighbouring 'mined' cells in the next
row, and similarly, from a 'not mined'(i.e. an empty cell) cell you can
only move to a neighbouring 'not mined' cell in the next row.
• If your current row number is even, you can move to any neighbouring
cell in the next row, irrespective of the mining.
You have to find the number of ways to reach row number N starting from row
number 1, modulo 10°+7. Two ways are different, if there is at least one
different cell on the paths. Find a pythonic approach for the solution and
develop a optimized python code. Sample inputs outputs are listed below:
Input:
1
25
Output:
8
Transcribed Image Text:In WW2, allies have placed their mines on the ground which can be considered as a gird of size N*M. Rows are numbered by integers from 1 to N and columns are numbered by integers from 1 to M. Each cell (i,j) has a mine in it if (i+j) is divisible by 2. All the other cells are empty. Two cells are neighbours if they share a boundary or a corner. Your aim is to move from the first row to the last row using some special rules that the automatic mine placing system follows. The mines won't blow if the following rules are followed: • If your current row number is odd, from a 'mined' cell (i.e. cell having a mine in it) you can move only to a neighbouring 'mined' cells in the next row, and similarly, from a 'not mined'(i.e. an empty cell) cell you can only move to a neighbouring 'not mined' cell in the next row. • If your current row number is even, you can move to any neighbouring cell in the next row, irrespective of the mining. You have to find the number of ways to reach row number N starting from row number 1, modulo 10°+7. Two ways are different, if there is at least one different cell on the paths. Find a pythonic approach for the solution and develop a optimized python code. Sample inputs outputs are listed below: Input: 1 25 Output: 8
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