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x- 1 L² p = Po wh the ond

x- 1 L² p = Po wh the ond

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7-Solve D-) with explain

(!) THE FOLLOWING QUESTIONS ARE BASED ON THE INFORMATION GIVEN HERE. A rod of semiconducting material of length L = 4 m and cross-sectional area A = 3.5 mm2 lies along the x-axis L. The material obeys Ohm's law, and its resistivity varies along the rod according to 0 and x = x2 1 between x = p = Po where po = 3 × 10-4 2 · m. The end of the rod at x = O is at a potential Vo 15 V greater than L² the end at x = L. A) What is the total resistance, in units of 2, of the rod?
Transcribed Image Text:(!) THE FOLLOWING QUESTIONS ARE BASED ON THE INFORMATION GIVEN HERE. A rod of semiconducting material of length L = 4 m and cross-sectional area A = 3.5 mm2 lies along the x-axis L. The material obeys Ohm's law, and its resistivity varies along the rod according to 0 and x = x2 1 between x = p = Po where po = 3 × 10-4 2 · m. The end of the rod at x = O is at a potential Vo 15 V greater than L² the end at x = L. A) What is the total resistance, in units of 2, of the rod?
D) What is the electric-field magnitude E, in units of V/m, in the rod at x = L/2?
Transcribed Image Text:D) What is the electric-field magnitude E, in units of V/m, in the rod at x = L/2?
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