X = 1 X = 2 X= 3 X=5 Y = 0 3/32 3/32 1/32 1/16 Y = 2 1/32 3/32 1/32 1/32 Y = 4 1/16 1/32 3/32 1/32 Y = 5 3/32 1/16 1/16 3/32 Find Joint Probability P(X≥2, Y≤2) P(X≥3, Y≥4) Find the Marginal PMF of Y=0 Y = 4 X = 5 X = 1 Find Conditional Probability P(X=3|Y=4) P(Y=4|X=1) Prove whether P(Y=4|X=1) & P(Y=4) are independent or not P(X=1, Y=0) are independent or not

X = 1 X = 2 X= 3 X=5 Y = 0 3/32 3/32 1/32 1/16 Y = 2 1/32 3/32 1/32 1/32 Y = 4 1/16 1/32 3/32 1/32 Y = 5 3/32 1/16 1/16 3/32 Find Joint Probability P(X≥2, Y≤2) P(X≥3, Y≥4) Find the Marginal PMF of Y=0 Y = 4 X = 5 X = 1 Find Conditional Probability P(X=3|Y=4) P(Y=4|X=1) Prove whether P(Y=4|X=1) & P(Y=4) are independent or not P(X=1, Y=0) are independent or not

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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	X = 1	X = 2	X= 3	X=5
Y = 0	3/32	3/32	1/32	1/16
Y = 2	1/32	3/32	1/32	1/32
Y = 4	1/16	1/32	3/32	1/32
Y = 5	3/32	1/16	1/16	3/32