Please do number 1 using C language 11. write a program using an array to perform the sum and average for the zig zag elements shown inthe above figure.

List of variables used: Considering an array "arr" of rows: 3 and columns: 5. Variables i,j,k for…

Answered: X 1. write a program using an array to…

C++ Programming: From Problem Analysis to Program Design

8th Edition

ISBN:9781337102087

Author:D. S. Malik

Publisher:D. S. Malik

Chapter8: Arrays And Strings

Section: Chapter Questions

Problem 15PE

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Question

Please do number 1 using C language

1
1. write a program using an array to perform the sum and average for the zig zag elements shown in
the above figure.

Expert Solution

Step 1

List of variables used:

Considering an array "arr" of rows: 3 and columns: 5.
Variables i,j,k for looping purpose.
Array sum[2]: to store the sum of given figures zigzag elements.
Array avg[2]: to store the average of zigzag elements given figures.
Array count[2]: To count the number of elements in zigzag

Finding and calculating sum and average of first zigzag elements:

variables i and j are used for accessing elements in the array.
- Where i represents the row.
- where j represents the column.
Initialize i=0, j=0 means accessing first-row first-element.
Loop for accessing rows begins with termination condition i<3
- Loop for accessing columns begins with termination condition j<=(i+1)
  - Adding arr[i][j] to sum[0].
    - sum[0] += arr[i][j]
  - Increase count value by 1.
    - count[0]++
  - Increase j value by 1.
  - If the termination condition j<=(i+1) satisfies, exit from the loop. Otherwise, repeat the loop.
- Increase value of i by 1.
- If the termination condition i<3 satisfies, exit from the loop. Otherwise, repeat the loop.
Calculating average of zigzag elemnts.
- avg[0]=sum[0]/count[0]

Finding and calculating sum and average of second zigzag elements:

variables i and j are used for accessing elements in the array.
- Where i represents the row.
- where j represents the column.
Initialize i=0, j=0 and k=4.
Loop for accessing rows begins with termination condition i<3
- Loop for accessing columns begins with termination condition j<5
  - if value of i equals to j ( j == i) then
    - Adding arr[i][j] to sum[1].
      - sum[1] += arr[i][j]
    - Increase count value by 1.
      - count[1]++
  - if value of k equals to j ( j == k) and value of i not equals to j (j != i) then
    - Adding arr[i][j] to sum[1].
      - sum[1] += arr[i][j]
    - Increase count value by 1.
      - count[1]++
  - Increase j value by 1.
  - If the termination condition j<5 satisfies, exit from the loop. Otherwise, repeat the loop.
- Increase value of i by 1.
- decrement value of k by 1.
- If the termination condition i<3 satisfies, exit from the loop. Otherwise, repeat the loop.
Calculating average of zigzag elemnts.
- avg[1]=sum[1]/count[1]

Step 2

CODE:

#include <stdio.h>

int main()

{

// Declaring variables for array, sum, average and looping.

int arr[3][5], sum[2] = {0};

float avg[2] = {0};

int i, j, k, count[2] = {0};

//Reading array elements

printf("Enter Array element of size 3 * 5:");

for (i = 0; i < 3; i++)

{

printf("\nEnter %d row 5 elements:\n", i + 1);

for (j = 0; j < 5; j++)

{

scanf("%d", &arr[i][j]);

}

//Displaying Array elements

printf("\nArray elements:");

for (i = 0; i < 3; i++)

{

printf("\n");

for (j = 0; j < 5; j++)

{

printf("%d\t", arr[i][j]);

}

// calculating sum and average of first zigzag elements

//Displatying First set of zigzag elements

printf("\nFirst zigzag puzzle:");

for (i = 0; i < 3; i++)

{

printf("\n");

for (j = 0; j <= (i + 1); j++)

{

printf("%d\t", arr[i][j]);

sum[0] += arr[i][j];

count[0]++;

}

avg[0] = (float)sum[0] / count[0];

// calculating sum and average of second zigzag elements

//Displatying second set of zigzag elements

printf("\nSecond zigzag puzzle:");

for (i = 0, k = 4; i < 3; i++, k--)

{

printf("\n");

for (j = 0; j < 5; j++)

{

if (j == i)

{

printf("%d", arr[i][j]);

sum[1] += arr[i][j];

count[1]++;

}

if (j == k && i != j)

{

printf("%d", arr[i][j]);

sum[1] += arr[i][j];

count[1]++;

}

printf(" \t");

}

avg[1] = (float)sum[1] / count[1];

//Dsipalying sum and averages of both first and second set of zigzag elements.

printf("\nFirst zigzag puzzle:");

printf("\n\tSum : %d", sum[0]);

printf("\n\tAverage : %f", avg[0]);

printf("\nSecond zigzag puzzle:");

printf("\n\tSum : %d", sum[1]);

printf("\n\tAverage : %f", avg[1]);

}

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X 1. write a program using an array to perform the sum and average for the zig zag elements shown in the above figure.