Can you help me finish it I am stuck 3 FindA =8↑the exactX = 2 sin ² tSin ³ tCOSAunder(sin²t) dt = 8yo dy dz²t tant) (4 costsint) dt = 8(y = 2 sint tant.dtthecost dt ="6²" (4-2-1* (* (* (1= cos (2+))*d*88parametricf4 costsint8-1 [² (1-2 cos (24) + cos² (2+)) d+(7p 717 यादH'f"- + cos (2+) + + cos² (24) d++ P₂ ( (72) 50 ~ 7 - 7)in ³ tant cost dt.curve7 7 7 7 0x212+ ] ² - 4 6² = cos(u) du +2 +3 So ² (1+ cos (4+)) dtdx7102 (= 1 dt -46 € (as (2+) oH + 2√² cos (2+) dzcos=2 sin²t = 2= ddt2 sintd 2 (sint) ²710= 2-2 Sint cost= 4 cost sintTrig Identitytan = Sin OCosoSin²t=1= costsin²t== 1/2 - 1/cos (2+)72=ndu = 2dtT = 7P= 1/2 ducos² (2+) = 1 + 1/2 cos (= = (1 + cos(4+))

We have to find the area under the parametric curve: x=2sin2ty=2sin2t tant And 0≤t≤π2. The formula…

Answered: x = 2sin²t y = 2sin't tant 4 륜 ㅋㅋㅋ ㅇ t

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x = 2sin²t y = 2sin't tant 4 륜 ㅋㅋㅋ ㅇ t

Functions and Change: A Modeling Approach to College Algebra (MindTap Course List)

6th Edition

ISBN:9781337111348

Author:Bruce Crauder, Benny Evans, Alan Noell

Publisher:Bruce Crauder, Benny Evans, Alan Noell

Chapter2: Graphical And Tabular Analysis

Section2.1: Tables And Trends

Problem 1TU: If a coffee filter is dropped, its velocity after t seconds is given by v(t)=4(10.0003t) feet per...

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Question

Can you help me finish it I am stuck

3 Find
A =
8
↑
the exact
X = 2 sin ² t
Sin ³ t
COSA
under
(sin²t) dt = 8
yo dy dz
²t tant) (4 costsint) dt = 8
(
y = 2 sint tant.
dt
the
cost dt =
"6²" (4-2-1
* (* (* (1= cos (2+))*d*
8
8
parametric
f
4 costsint
8-1 [² (1-2 cos (24) + cos² (2+)) d+
(
7p 717 याद
H
'f"
- + cos (2+) + + cos² (24) d+
+ P₂ ( (72) 50 ~ 7 - 7)
in ³ tant cost dt.
curve
7 7 7 7 0
x
2
12+ ] ² - 4 6² = cos(u) du +2 +3 So ² (1+ cos (4+)) dt
dx
710
2 (= 1 dt -46 € (as (2+) oH + 2√² cos (2+) dz
cos
=2 sin²t = 2
= d
dt
2 sint
d 2 (sint) ²
710
= 2-2 Sint cost
= 4 cost sint
Trig Identity
tan = Sin O
Coso
Sin²t=1= cost
sin²t=
= 1/2 - 1/cos (2+)
72=n
du = 2dt
T = 7P
= 1/2 du
cos² (2+) = 1 + 1/2 cos (
= = (1 + cos(4+))

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