x₁ = 3₁ y₁ = 2₁ 1₁₁ = - 13. yo 2, Ң, Two points P(xo, Yo), Q(x₁, y₁) are given. 1. Using the DDA algorithm, find the first 10 pixels to draw a straight line from P to Q. 2. Using the midpoint line algorithm (and 8-way symmetry), find the first 10 pixels to draw a straight line from P to Q. 3. Which of the above algorithms (1 and 2) is more efficient? Justify your answer. Note: Drawing a straight line from P to Q isn't the same as drawing a straight line from Q to P. The output is the same, but the algorithm will vary. 3 O 4 2 1 P - 13₁ y₁ = 21 5 6 0 7 Figure 1: Different octants (PQ in octant 2) Y

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
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Give me the answer to the question number 2
K₁ = 3₁ y₁ = 2₁ x ₂₁ = -13,
*o 3, yo
2,
Two points P(xo, Yo), Q(x₁, y₁) are given.
1. Using the DDA algorithm, find the first 10 pixels to draw a straight line from
P to Q.
Ң, · y₁ = 2
21
2. Using the midpoint line algorithm (and 8-way symmetry), find the first 10
pixels to draw a straight line from P to Q.
3. Which of the above algorithms (1 and 2) is more efficient? Justify your
answer.
Note:
Drawing a straight line from P to Q isn't the same as drawing a straight line from Q
to P. The output is the same, but the algorithm will vary.
3
4
2 1
P
5
6
0
7
Figure 1: Different octants (PQ in octant 2)
Y
O
X
Transcribed Image Text:K₁ = 3₁ y₁ = 2₁ x ₂₁ = -13, *o 3, yo 2, Two points P(xo, Yo), Q(x₁, y₁) are given. 1. Using the DDA algorithm, find the first 10 pixels to draw a straight line from P to Q. Ң, · y₁ = 2 21 2. Using the midpoint line algorithm (and 8-way symmetry), find the first 10 pixels to draw a straight line from P to Q. 3. Which of the above algorithms (1 and 2) is more efficient? Justify your answer. Note: Drawing a straight line from P to Q isn't the same as drawing a straight line from Q to P. The output is the same, but the algorithm will vary. 3 4 2 1 P 5 6 0 7 Figure 1: Different octants (PQ in octant 2) Y O X
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