(x + 5) dx V4 - x2

Q: x2 -dx Vx² + 18

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Q: Integrate

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Q: Vx-x (-X dx 4. x3

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Q: (3x-2) dx f x²+ 2x + 15

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Q: Vx - 3 dx x=3

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Q: III. Evaluate 4 - x -dx. V16 – x2

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Q: 2x - 2x2-3 dx - Find 4 x* + x²

A: To evaluate: ∫2x3−2x2−3x4+x2dx Let, I=∫2x3−2x2−3x4+x2dx ⇒I=∫2x3−2x2−3x2x2+1dx

Q: (x²-2x+11)dx (x²+3x-4) .2. r2.

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Q: 3. 9x -dx (x² +7)

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Q: dx (10. V3-2x-x2

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Q: Integrate the function. dx , x > 8 2/x2-64

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Q: Evalvate 5x-12 X (x²+4) dx

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Q: -dx x2 + 2

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Q: V2/2 -3x2 dx 1 – x²

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Q: x* - 2x2 +3 dx 31 Vx2

A: We’ll answer the first question since the exact one wasn’t specified. Please submit a new question…

Q: V9 - x dx -3

A: Given: I=∫-339-x2dx for finding given integral we will given below property…

Q: 2x ²-11)dx x3+3x²-4

A: To evaluate the integral.

Q: (x2 - 4x + 4)4/3 dx -

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Q: 3-4x-10 x²-x-6 dx.

A: Given integral ∫x3-4x-10x2-x-6dx. The objective is to evaluate the integral.

Q: 2. x°ー×- 8x ー1 dx x²-3X -4 2

A: according to our guidelines we can answer only three subparts, or question and rest can be reposted.…

Q: (а) / х V2х — 1 dx (b) dx e4x +1

A: (a) Given data:   The given integral is: Assume 2x-1=t and differentiate it with respect to x.…

Q: 4 - x -dx. 16 – x2 III. Evaluate

A: Solving

Q: (2x2-x+6)dx (х2—х-2))

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Q: d -(f(x² + 3x)) dx

A: Derivative

Q: V1+ x² dx 2.

A: Follow the procedure given below

Q: 3x-6 dx VE-2

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Q: S (2 + x)dx √4-2x-x²

A: We can solve the integration as below.

Q: x-3 dx V16-x² (16-х2

A: Given,          ∫x-316-x2dx

Q: g3 +5x²+9x+7 dx dæ Evaluate x²+5x+4

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Q: \ dx lox-x+15 (2X-1)(x4)

A: use partial fraction  ...................(1) ...................(2) take x=1/2 ..............put…

Q: dx x'V4 - x² メー 」

A: The given integral is: ∫12dxx24-x2 Substitute x = 2sint, so dx = 2costdt When x = 1, t=π6 When x =…

Q: Sx V1 – x² dx 3.

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Q: V4- V4-x dx 11.

A: Solution of question as follows

Q: Find:

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Q: 2Rx-3 + (x² – 3)] dx а. - (Rx2-3x+1)5

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Q: dx J-25a2 1–25x² -25x2 8.

A: The objective is to evaluate the integration.

Q: V4.x2 – 9 -dx

A: Solution of question is written in below steps.

Q: X-1 dx -x² - 4x- 2

A: Given, ∫x-1-x2-4x-2dx  We have to integrate it

Q: x-6x-4 dx x+2

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Q: V1+x3 –dx r-2

A: ∫1+x33x-2 dx∫x2.1+x33 dx13∫3x2.1+x33 dx13∫3x2.(1+x3)13 dx

Q: Evaluate:

A: Given integral is We know that

Q: V2-x dx

A: We use substitution method to solve this integration

Q: SV2*- 16 dx 2.x

A: Consider the integral: ∫e2x−16dxApply u…

Q: xª – 5x³ + 6x² 5a3 + 6x2 — 18 dx x³ – 3x2 -

A: The given integral is: ∫x4-5x3+6x2-18x3-3x2dx Let, I=∫x4-5x3+6x2-18x3-3x2dx

Q: YOUR TURN 3 x + 1 Find dx. (4x² + 8x)³

A: We need to evaluate the integral. We will make use of the substitution: 4x2 + 8x = u Hence, (8x + 8)…

Q: x2 dx 21. 7-5x3

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Q: 6 dx エニ 3-2x -x2

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Q: X 2 dx = V4-x2

A: I=∫01x24-x2dx =∫01(4-x2)+44-x2dx =∫014-x24-x2dx+∫0144-x2dx =∫014-x2dx+4∫0114-x2dx Here  ⇒∫a2-x2…