X+ y- 3z = 815. Using back-substitution, what is the solution of the linear system.y- 3z = 3?Z = -2A. x = 5,y = -3, z = -2В. х %3D — 3, у %3 5,z%3D—2C. x = 4, y = -3, z = -2D. x = -5, y = 3,z = -2

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x+ y- 3z = 8 y- 3z = 3? 15. Using back-substitution, what is the solution of the linear system Z = -2 A x = 5,y = –3, z = -2 В. х %3D— 3, у %3 5,z%3D—2 C. x = 4, y = -3,z = -2 D. x = -5,y = 3,z = -2

x+ y- 3z = 8 y- 3z = 3? 15. Using back-substitution, what is the solution of the linear system Z = -2 A x = 5,y = –3, z = -2 В. х %3D— 3, у %3 5,z%3D—2 C. x = 4, y = -3,z = -2 D. x = -5,y = 3,z = -2

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018

18th Edition

ISBN:9780079039897

Author:Carter

Publisher:Carter

Chapter6: Systems Of Linear Equations And Inequalities

Section: Chapter Questions

Problem 18SGR

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Question

X+ y- 3z = 8
15. Using back-substitution, what is the solution of the linear system.
y- 3z = 3?
Z = -2
A. x = 5,y = -3, z = -2
В. х %3D — 3, у %3 5,z%3D—2
C. x = 4, y = -3, z = -2
D. x = -5, y = 3,z = -2

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