Find the current through thegalvanometer and the resistance R₁, R₂, R3 and R₁in the Wheatstone's network. If I = 10mA, R₁100, R₂ = 200., R₂ = 2002, R₁ = 1002 and G = 100.=301A 10-x10 mA20 QwwwBEx - l₂www10020:0210 -x + Igto 100KC

The given problem is from wheatstone bridge. The detailed solution is given in the next step

Answered: Find the current through the…

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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Finding the direction of the currents. Finding currents given that R2: 10.94 x 10^2 ohmR3: 9.89 x 10^2 ohmR4: 25 ohm Terminal Potential: Battery 1: 5 V using Kirchoff's laws. You will check some of the laws that govern electrical circuitsDirect current: conservation of current in a node, addition of potentialsfor series components, addition of currents for parallel components
HI PLEASE HELP ME SOLVE FOR V1,V2,V3, I1, I2, I3, TOTAL CURRENT VT = 50V R1=201 R2=420 R3=16 the answers are already provided in the picture, all i need is the solution .. thank you verymuch
HI PLEASE HELP ME SOLVE FOR V1,V2,V3, I1, I2, I3, IT VT = 50V R1=201 R2=420 R3=16 the answers are already provided in the picture, all i need is the solution .. thank you verymuch
solve using thevenins theorem(draw the step by step changes in the circuit diagram)solve the computed values1. RTH (measured values from tinkercad=56.8 ohms)2. VTH (measured values from tinkercad=2.27 V)3. I (measured values from tinkercad=0.04 A)
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The figure below shows a multiloop circuit. The voltages and resistances in the circuit are: V1 = 10.0 V, V2 = 30.0 V, V3 = 58.0 V, R1 = 125.0 Ω, R2 = 155.0 Ω, R3 = 195.0 Ω. Use these values to answer the questions below. (Use the following as necessary: I1, I2, and I3.) WikiHow LOGO (a) Write the equation for the loop ABHEFGA in the order that you go around the loop. −I2 (155.0 Ω) −30.0 V + 10.0 V − I1 (125.0 Ω) = 0 +I2 (155.0 Ω) +30.0 V +10.0 V − I1 (125.0 Ω) = 0 +I3 (155.0 Ω) +58.0 V −10.0 V − I2 (155.0 Ω) = 0 −I3 (195.0 Ω) −58.0 V +10.0 V − I1 (155.0 Ω) = 0 (b) Write the equation for the loop BCKDEHB in the order that you go around the loop. +I2 (155.0 Ω) +30.0 V +10.0 V − I1 (125.0 Ω) = 0 +I3 (195.0 Ω) −58.0 V + 30.0 V + I2 (155.0 Ω) = 0 +I3 (155.0 Ω) +58.0 V −10.0 V − I2 (155.0 Ω) = 0 −I3 (195.0 Ω) −58.0 V +30.0 V − I1 (155.0 Ω) = 0 (C) Write the equation for the loop ABCKDEFGA in the order that you go around the loop. +I3 (155.0 Ω) +30.0 V −58.0 V − I2…
3Draw the circuit diagram an solve using ohms law asap pls 3. Two lamps rated 100W and 200V areconnected in series across 200V supply . Find the power consumed by each lamp
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Find the current through the galvanometer and the resistance R₁, R₂, R3 and R₁ in the Wheatstone's network. If I = 10mA, R₁ H 100, R₂ = 200., R₂ = 2002, R₁ = 1002 and G = 100. 100 A 10-x 10 mA 20 Q2 www B E x - l₂ www 100 20:02 10 -x + Ig to 100 K C