x2 -x-6 2. lim -2 x2 -2

Q: 2) Lim 나-13 X+ 1 x=7x+10

A:

Q: 1. lim -4x +7 = -1 X-2

A:

Q: (a) 5x-3 - 4. (i) Lim x-0 2x-2 +9 (х — 3)2 (ii) Lim X-00 x2 — 2х-3

A: To find the limits

Q: x² – 9 - lim x--3 x² + 2x – 3

A: The given function is limx→-3x2-9x2+2x-3

Q: x² - x-6 lim x-2 x2 +3x+2

A: L'Hospital Rule: If limx→af(x)g(x)=00      Indeterminant forThenlimx→af(x)g(x)=limx→addxf(x)ddxg(x)…

Q: 3. lim- 2x+ 4 3 X→- X-4 4. lim x→2 x2-6x+8

A:

Q: (а) 5x-3 – 4 (i) Lim X0 2x-2 +9 (х - 3)2 (ii) Lim- X0 X2 7- 2x – 3

A: We must know that 1∞=0 And here the  limits are (i)  -49     and (ii) 2

Q: x²-4 (b) lim 4-2 X+2

A: We have to evaluate the limit: blimx→-2x2-4x+2 After putting limit value we get that it is in the…

Q: x5-5x-12 1. lim х—2 х10-500х-24

A:

Q: 9. lim -2x-15 (3r-2)-(x+2) 10. lim -5 x-5 x-2

A: The limit of a function (expression ) is a value of that function (expression ) that approaches as…

Q: x2 -x-2 lim 12 x- 2x X-2

A:

Q: lim (-2x – 6) X-8-

A:

Q: х2 + 2у lim (х.у)-(0.0) 1 — е*-у!

A: Explained below

Q: Зx2-х-64 17.lim х-4 х2-х-12 10х2-7 18. lim х-о Зx2-х-12 х3-81 19. lim х-0о Зx2+4x+2

A: We will solve the problem.  L.Hospital Rule will be used in the problem.

Q: 8) lim- x+1 2x²+2x+1

A:

Q: डणि2X Lim 2. x²

A: We have to find the limit of given function.

Q: x*-2x2-x с- lim x-2 , х 2 2 х2-4

A:

Q: Evaluate the following limits.

A: If any function is continuous within a given interval, then its limit must exist in that interval.…

Q: (а) 5x-3 – 4 (i) Lim x-00 2x-2 + 9 (х— 3)2 (ii) Lim X00 x2 7- 2x – 3 2 - 2х

A:

Q: x3 - x2 - 5x lim x-1 - 2 (x + 1)2.

A:

Q: 4-x 1) lim x→2+ x² –3x+2

A:

Q: 4x lim *-3 2- V2х + 3

A:

Q: (а) 5x-3 – 4 (i) Lim x-00 2x-2 +9 (х — 3)2 (ii) Lim x-00 x2 7- 2x – 3 2

A:

Q: √2+x-√2-x X lim- --0

A:

Q: х3 — а3 lim х--а х4 — а4 x-a

A: Given  limx→ax3-a3x4-a4   We have to evaluate the limit.

Q: (а) 5x-3 – 4 (i) Lim X00 2x-2 + 9 (х - 3)2 (ii) Lim- X0 x2 7- 2x - 3

A: Here, solving only two subparts of Question number 4 and for the remaining post the question again.…

Q: Vx2-3-2. 7. lim x2 +1 х->-1 Зх -V6 — х 8. lim х->-1 4 + x2

A: (7) We have to evaluate the following limits -  limx→-1x2-3-2x2+1Applying limits i.e. put x = -1 we…

Q: x2-x-6 2) FIND limx-→3 x2-5x+6"

A: We will solve the problem

Q: V2 lim x-2 x- 2

A:

Q:

A:

Q: ]x - 5| lim 3x-15 x5-

A:

Q: 2+3t+2 lim -1 2-t-2 (ii).

A: Given limit: limt→-1 t2+3t+2t2-t-2

Q: 2х3-2 lim х-1/(х-1)2 x→1

A: It is given that,    limx→1 2x3-2x-12 We have to evaluate it.

Q: (a) lim- エ→4 Vř -16 (b) lim- (1–x)² エー

A:

Q: (а) 5x-3 – 4 (i) Lim- x-00 2x-2 +9 (х— 3)2 (ii) Lim X-00 X T- 2x – 3

A:

Q: lim メ-2 ー×t6-× 2. 12-X X +6

A: Solving

Q: 1 lim х-2 х — 2

A:

Q: lim メ→-4 Vx+4 - 2

A:

Q: (а) 5x-3 – 4 (i) Lim- x--00 2x-2 +9 (х— 3)2 (iї) Lim X-0 x2 7- 2x – 3 2х —

A: (i) Obtain the limit as follows.…

Q: Find the limits

A: Find the limits

Q: (а) 5x-3 – 4 (i) Lim X-0 2x-2 + 9 (х — 3)2 (ii) Lim 7- 2x -3 2х — 3

A: to solve the limit proceed as follows…

Q: 5x-3 – 4 (i) Lim: X-00 2x-2 + 9 (x – 3)2 (ii) Lim - 2x- 3 2

A: (i)

Q: x² - 1 1. lim- x→1 x2 +3x - 4

A: NOTE*** As per bartleby guidelines for more than one question asked only first is to be answered…

Q: ■ Find the limit.

A: We have to find the limit: limx→-3+x+2x+3 Since x→a+ denotes the right hand limit of the function.…

Q: x³ – - 3x 2x² 5. lim X--5 x² - x

A:

Q: 3x-2x 7. lim- X0 x2-x 8. lim x→∞ x²(ex – 1)

A:

Contingency Table

A contingency table can be defined as the visual representation of the relationship between two or more categorical variables that can be evaluated and registered. It is a categorical version of the scatterplot, which is used to investigate the linear relationship between two variables. A contingency table is indeed a type of frequency distribution table that displays two variables at the same time.

Binomial Distribution

Binomial is an algebraic expression of the sum or the difference of two terms. Before knowing about binomial distribution, we must know about the binomial theorem.