x(k)-3x(k-1)+2x(k-2)= e(k), e(k)= [1, k = 0, 1 0, k ≥ 2 x(-2) = x(-1) = 0

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter5: Inverse, Exponential, And Logarithmic Functions
Section5.6: Exponential And Logarithmic Equations
Problem 64E
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Find x(k) by using z-transform

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x(k)-3x(k-1) + 2x(k − 2) = e(k), e(k)=
[1, k = 0, 1
0, k ≥2
x(-2) = x(-1)=0
Transcribed Image Text:- x(k)-3x(k-1) + 2x(k − 2) = e(k), e(k)= [1, k = 0, 1 0, k ≥2 x(-2) = x(-1)=0
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How should x(-2) = x(-1) = 0 be used in the question. And it contradicts the expression obtained for x(k)

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