Ex. 929. See Fig. 929. Replace: 18 w/ -16, 40 w/ -6, -30 w/ 4, -24 w/ -9,and 10 w/8. The fundamental frequency is 13000 Hz.Find a b.c.d.e.f.g.h,k ans:9x(t) = 18 + 40 cos 20007Tt30 sin 20007t-24 cos 4000nt + 10 sin 40001x(t) = a + ( b + jc)em+ ( d +je )e¯e ajwt+( f +jg)ewt + ( h +jk )e j2wtFigure 929

Answered: Image /qna-images/answer/ccbd6533-9b2c-4225-a989-f0773c701183.jpg

Answered: x(t) = 18 + 40 cos 20007rt 30 sin…

x(t) = 18 + 40 cos 20007rt 30 sin 20007t %3D - -24 cos 4000Tt + 10 sin 4000Tt x(t) = a + ( b + jc)e™* + ( d + j e )e¯ We a %3D jwt +( f +jg)e☆ws + ( h +j k )e i2wt Figure 929

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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FIND H(Z).Find the resultant frequency response H(z) of the system of the photo shown.( NEED ONLY HANDWRITTEN SOLUTION PLEASE OTHERWISE DOWNVOTE).
a- find the instantaneous frequency for the following signals 1- S, = 8cos[1600nt2 + 47 * 1600t + 500] 2- S = 4 sin[3200 nt + 0.8 sin(500t)] b- For the circuit shown below, find the frequency domain of the o/p signal and draw the spectrum 4cos(2n 800t) Х 2cos(2n * 1800t)
In the circuit in the figure, Vcc = 18 V, Rs1 = 0.9 kΩ, Rs2 = 0.5 kΩ, R1 = 75 kΩ, R2 = 15 kΩ, RC = 2.2 kΩ, RE = 1 kΩ and β =120. It is also known that Cwi = 6 pF, Cwo = 10 pF, Cbc = Cu = 7 pF, Cbe = Cπ = 46 pF and Cce = 11 pF. Accordingly, considering the frequency response of the circuit, what would be the high cutoff frequency (fH)? NOTE-1: The output impedance of the transistor is r0 = 20 kΩ and will be taken into account in the calculations. NOTE-2: The high frequency dependence of hfe, β, will not be taken into account.
In the circuit in the figure, Vcc= 18 V, Rs1 = 0.9 kohm, Rohm = 0.5 kQ, R1 = 75 kohm, R2 = 15 kohm, RC = 2.2 kohm, RE = 1 kohm and B = 120. It is also known that Cwi = 6 pF, Cwo = 10 pF, Cbc = Cu = 7 pF, Cbe = C = 44 pF and Cce = 11 PF. Accordingly, considering the frequency response of the circuit, what would the high cutoff frequency (fH) be? NOTE-1: The output impedance of the transistor is ro = 20 k and will be taken into account in the calculations. NOTE-2: high frequency dependence of hfe, B. will be taken into account.
In the circuit in the figure, Vcc = 18 V, Rs1 = 0.9 kΩ, Rs2 = 0.5 kΩ, R1 = 75 kΩ, R2 = 15 kΩ, RC = 2.2 kΩ, RE = 1 kΩ and β =120. It is also known that Cwi = 6 pF, Cwo = 10 pF, Cbc = Cu = 7 pF, Cbe = Cπ = 48 pF and Cce = 11 pF. Accordingly, considering the frequency response of the circuit, what would be the high cutoff frequency (fH)? NOTE-1: The output impedance of the transistor is r0 = 20 kΩ and will be taken into account in the calculations. NOTE-2: The high frequency dependence of hfe, β, will be taken into account. a. 719,95 kHz b. 143,99 kHz c. 48,00 kHz d. 191,99 kHz e. 575,96 kHz f. 479,97 kHz g. 335,98 kHz h. 623,96 kHz
Q2.The current versus angular frequency o for a resonant RLC series circuit is given in the graph. The inductance(L) is 20 µ H and the peak voltage(Vo) of AC source is 8V. a) Find Capacitance(C) and Resistance(R). b) What is the phase difference(@) of this circuit at o,=25,000 rad/s?
In the circuit in the figure, Vcc= 18 V, Rs1 = 0.9 k2, Rs2 = 0.5 kQ, R1 = 75 kQ, R2 = 15 kQ, RC = 2.2 kQ, RE = 1 k and B = 120. It is also known that Cwi = 6 pF, Cwo = 10 pF, Cbc = Cu = 7 pF, Cbe = C = 44 pF and Cce = 11 PF. Accordingly, considering the frequency response of the circuit, what would the high cutoff frequency (fH) be? NOTE-1: The output impedance of the transistor is ro = 20 k and will be taken into account in the calculations. NOTE-2: high frequency dependence of hfe, B. will be taken into account.
388 / 5000 Çeviri sonuçları In the circuit in the figure, Rs = 3.8 kΩ, R1 = 82 kΩ, R2 = 22 kΩ, RC = 5.6 kΩ, RE = 1.5 kΩ and RL = 3.3 kΩ and β = 150.Since the capacitances are C1 = 0.5 μF and C2 = 0.53 μF, what is the low cutoff frequency of the given circuit? NOTE-1: In the middle band frequency, β = 150 will be taken and the frequency dependence of β will not be taken into account. NOTE-2: The output impedance of the transistor r0 will be neglected in the calculations.
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