Y, = 0.2 Y, = -0.7 Y, = 0.8 Y, = -0.9 Based on this diagram of two plant cells, what direction do you expect water to move? (Calculate the water potentials for each cell to determine the direction) Select one: O a. A to B O b. B to A O c. No movement O d. You cannot tell based on this information
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- If I slid a plant cells with a water potential averaging -.5 MPa Are placed into solution with a water potential of -.3 MPa, which of the following would be the most likely outcome?1) A plant cell with a pressure potential of 5 bars and an osmotic potential of -9 bars is in equilibrium with a surrounding solution that is open to the air. What is the water potential of the surrounding solution? 2) A plant cell, when initially placed in pure water, has an osmotic potential of -4 bars and a pressure potential of +2 bars. a) Which way will water diffuse? b) When will net diffusion stop? c) When equilibrium is reached, what are the cell's osmotic potential and pressure potential values?Water will always move from an area of high water potential to low water potential. If you drop a cell with WP = 0 into the water with WP = -0.9, then what will happen to the cell?
- You place a flaccid plant cell (Ψ = -0.7 MPa) into an environment (beaker) of pure (deionized) water (Ψ = 0 MPa). Compare the initial conditions of the flaccid cell and the environment (beaker of pure water) in terms of: D) Water potential (high or low) of the cell E) Solute concentration (high or low) of the cell F) Tonicity (hypertonic, hypotonic, or isotonic) of the cellConsider a plant cell. The value for solute concentration in a plant cell is -0.12 MPa and the turgor pressure is 0.12 MPa. 1- What is the water potential in this plant cell? 2- If this plant cell were placed in a solution with water potential of -0.1 MPa, what would happen to the cell? (Hint: explain where the water goes and what that does to the cell).If you place a flaccid plant cell with ΨS = -0.4 MPa in pure water, which of the following will occur? A. Water will not enter the cell because the flaccid cell has solutes and low water potential. B. Water enters the cell because the flaccid cell has solutes and low water potential. C. Water enters the cell because the flaccid cell has solutes and high water potential. D. Water will not enter the cell because the flaccid cell has solutes and high water potential.
- Which of the following is true of the water potential of a healthy living plant cell? ( SELECT ALL THAT APPLY) A. It has a higher solute potential (lower solute concentration) than the extracellular environment B. It is under negative pressure C. It has a lower solute potential (high solute concentration) than the extracellular enviroment D. It is under positive pressure E. It has a pressure potential equal to zeroThe osmotic potential of the plant cell is -0.1 MPa and it is placed in an 9 mM sorbitol solution (21 °C). Calculate the turgor pressure of the cell when the water potential of the cell has equilibrated to the same as that of the solution.You place a flaccid plant cell (Ψ = -0.7 MPa) into an environment (beaker) of pure (deionized) water (Ψ = 0 MPa). Compare the initial conditions of the flaccid cell and the environment (beaker of pure water) in terms of: A) Water potential (high or low) of the environment B) Solute concentration (high or low) of the environment C) Tonicity (hypertonic, hypotonic, or isotonic) of the environment D) Water potential (high or low) of the cell E) Solute concentration (high or low) of the cell F) Tonicity (hypertonic, hypotonic, or isotonic) of the cell G) Predict the direction of water movement (into the cell, out of the cell, or no net movement) H) Predict the change in turgor pressor of the cell (increase turgor pressure or decrease turgor pressure) I) Predict the fate of the cell (plasmolyzed, turgid, or lysed)
- Water potential a) The value for Ψ in root tissue was found to be -3.3 bars. If you take the root tissue and place it in a 0.1 M solution of sucrose at 20°C in an open beaker, what is the Ψ of the solution, and in which direction would the net flow of water be? b) NaCl dissociates into 2 particles in water: Na+ and Cl-. If the solution in question 4 contained 0.1M NaCl instead of 0.1M sucrose, what is the Ψ of the solution, and in which direction would the net flow of water be? c) A plant cell with a Ψs of -7.5 bars keeps a constant volume when immersed in an open-beaker solution that has a Ψs of -4 bars. What is the cell’s ΨP?If a human lacks a protein like laminin in the ECM, this results in serious deformity. Why don’t plants have this problem? Select one: a. Plants have an excess of laminin so their ECM is well linked. b. Plants do have connection problems due to proteins missing in their ECM. c. Plants have fibronectin to replace laminin and maintain cell wall connections. d. Plants do not have an ECM and are joined by the middle lamella between their cell wallsA daisy stem is placed in a solution with a water potential of -0.2 bars. After the daisy stem cells have had a chance to reach equilibrium with the surrounding solution, the pressure potential inside the daisy cells is 0.5 bars. At equilibrium, calculate the solute potential of the daisy cells.